如何使用MSVC每次使malloc返回相同的地址? [英] How to make malloc return the same address every time using MSVC?

问题描述

出于调试目的，我希望 malloc 每次执行程序时都返回相同的地址，但是在MSVC中并非如此.例如:

For debugging purposes, I would like malloc to return the same addresses every time the program is executed, however in MSVC this is not the case. For example:

#include <stdlib.h>
#include <stdio.h>

int main() {
    int test = 5;
    printf("Stack: %p\n", &test);
    printf("Heap: %p\n", malloc(4));
    return 0;
}

使用cygwin的gcc进行编译时，每次都会获得相同的堆栈地址和堆地址，而在关闭aslr的情况下使用MSVC进行编译...

Compiling with cygwin's gcc, I get the same Stack address and Heap address everytime, while compiling with MSVC with aslr off...

cl t.c /link /DYNAMICBASE:NO /NXCOMPAT:NO

...我每次都获得相同的堆栈地址，但是堆地址会更改.

...I get the same Stack address every time, but the Heap address changes.

我已经尝试添加注册表值 HKLM \ SYSTEM \ CurrentControlSet \ Control \ Session Manager \ Memory Management \ MoveImages ，但是它不起作用.

I have already tried adding the registry value HKLM\SYSTEM\CurrentControlSet\Control\Session Manager\Memory Management\MoveImages but it does not work.

推荐答案

事实证明，您可能无法从MSVC运行时库中获得确定性行为.C/C ++运行时库的调试版本和生产版本都最终调用了名为 _malloc_base()的函数，该函数又调用了Win32 API函数

It turns out that you may not be able to obtain deterministic behaviour from the MSVC runtime libraries. Both the debug and the production versions of the C/C++ runtime libraries end up calling a function named _malloc_base(), which in turn calls the Win32 API function HeapAlloc(). Unfortunately, neither HeapAlloc() nor the function that provides its heap, HeapCreate(), document a flag or other way to obtain deterministic behaviour.

您可以按照@Enosh_Cohen的建议，在 VirtualAlloc()之上汇总自己的分配方案，但是随后您将

You could roll up your own allocation scheme on top of VirtualAlloc(), as suggested by @Enosh_Cohen, but then you'd loose the debug functionality offered by the MSVC allocation functions.

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