用Math.Round获取一个可被5整除的数字 [英] Getting a number divisible by five with Math.Round

问题描述

我有一个介于0到100之间的数字变量.它可能类似于83.333334.

I have a number variable that is between 0 and 100. It ccould be something like 83.333334.

我想使用 Math.Round 舍入数字(例如 Math.round(83.333334); ).我该怎么做才能使结果始终被5整除(即在[0，5，10，15 ... 85，90，95，100]中)?

I want to use Math.Round to round the number (e.g. Math.round(83.333334);). How can I do this so that the result is always divisible by five (i.e. in the set [0, 5, 10, 15... 85, 90, 95, 100])?

推荐答案

除以5，将其四舍五入，再乘以5.

Divide by 5, round it, multiply by 5.

alert(Math.round(83 / 5) * 5);

jsFiddle演示

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