简单地要求在斯威夫特的网址 [英] Simply request an url in Swift

问题描述

我已经运行的点亮LE​​D的输入网址（... /？LEDON），并键入（... /？ledOff）时将其关闭时对我的Arduino的一个非常基本的Web服务器。

现在我已经找到了如何这两种状态用一个非常简单的寻找目标C code从本网站控制<一个视频href=\"http://www.raywenderlich.com/15932/electronics-for-iphone-developers-tutorial-control-a-led-from-your-iphone\"相对=nofollow>这里：

   - （IBAction为）开关pressed：（ID）发送{
    UISwitch *精选完美男=（UISwitch *）寄件人;
    如果（theSwitch.isOn）{
        NSURL * URL = [NSURL URLWithString：@？... / LEDON];
        *的NSURLRequest REQ = [的NSURLRequest requestWithURL：URL]
        [myWebView的loadRequest：REQ]
    }
}
 

于是，我就这样code转换成快捷，但有一个错误，在创建 NSURL 变量，我得到类型的变量 NSURL？

---

目前雨燕的尝试是这样的：

  VAR URL = NSURL（串：... / buttonOn）
VAR reqest =的NSURLRequest（网址：NSURL（URL））
 

解决方案

我建议用 NSURLSession 调用替换Web视图。这，顺便说一句，无需建的NSURLRequest 了。

因此​​：

  @IBAction FUNC开关pressed（发件人：UISwitch）{
    如果sender.on {
        让URL = NSURL（串：... / LEDON）！
        让任务= NSURLSession.sharedSession（）。dataTaskWithURL（URL）{数据，回应，误差
            //解析`data`或检查`这里error`，例如
            //
            //如果错误！= {为零
            //的println（\\（错误））
            //}
        }
        task.resume（）
    }
}
 

或者，如果你需要更新UI报告错误，请确保派遣了回主队列：

  @IBAction FUNC开关pressed（发件人：UISwitch）{
    如果sender.on {
        让URL = NSURL（串：... / LEDON）！
        让任务= NSURLSession.sharedSession（）。dataTaskWithURL（URL）{数据，回应，误差
            如果错误！= {为零
                dispatch_async（dispatch_get_main_queue（））{
                    //更新UI报告错误这里
                }
            }
        }
        task.resume（）
    }
}
 

I have running a very basic web server on my arduino which turns the led on when typing in the url (.../?ledOn) and turning it off when typing in (.../?ledOff).

Now i have found a video on how to control these two states with a very simple looking objective c code from this website here:

- (IBAction)switchPressed:(id)sender { 
    UISwitch *theSwitch = (UISwitch *) sender; 
    if (theSwitch.isOn) { 
        NSURL *url = [NSURL URLWithString:@".../?ledOn"]; 
        NSURLRequest *req = [NSURLRequest requestWithURL:url]; 
        [myWebView loadRequest:req]
    }
}

So i tried to convert this code into swift, but there is an error, while creating the NSURL variable, I get a variable of type NSURL?

---

The current Swift attempt looks like:

var url = NSURL(string: ".../?buttonOn") 
var reqest = NSURLRequest(URL: NSURL(url))

解决方案

I'd suggest replacing web view with NSURLSession call. This, by the way, eliminates the need to build the NSURLRequest, too.

Thus:

@IBAction func switchPressed(sender: UISwitch) {
    if sender.on {
        let url = NSURL(string: ".../?ledOn")!
        let task = NSURLSession.sharedSession().dataTaskWithURL(url) { data, response, error in
            // parse `data` or examine `error` here, e.g.
            //
            // if error != nil {
            //     println("\(error)")
            // }
        }
        task.resume()
    }
}

Or, if you need to update the UI reporting the error, make sure to dispatch that back to the main queue:

@IBAction func switchPressed(sender: UISwitch) {
    if sender.on {
        let url = NSURL(string: ".../?ledOn")!
        let task = NSURLSession.sharedSession().dataTaskWithURL(url) { data, response, error in
            if error != nil {
                dispatch_async(dispatch_get_main_queue()) {
                    //update UI reporting error here
                }
            }
        }
        task.resume()
    }
}

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