从matplotlib中的给定颜色图创建颜色生成器 [英] Create a color generator from given colormap in matplotlib

问题描述

我有一系列线，每条线都需要用单独的颜色绘制.每条线实际上由几个数据集(正区域、负区域等)组成，因此我希望能够创建一个生成器，该生成器将在光谱中一次提供一种颜色，例如 gist_rainbow 地图 此处显示.

I have a series of lines that each need to be plotted with a separate colour. Each line is actually made up of several data sets (positive, negative regions etc.) and so I'd like to be able to create a generator that will feed one colour at a time across a spectrum, for example the gist_rainbow map shown here.

我找到了以下作品，但看起来很复杂，更重要的是难以记住，

I have found the following works but it seems very complicated and more importantly difficult to remember,

from pylab import *

NUM_COLORS = 22

mp = cm.datad['gist_rainbow']
get_color = matplotlib.colors.LinearSegmentedColormap.from_list(mp, colors=['r', 'b'], N=NUM_COLORS)
...
# Then in a for loop
    this_color = get_color(float(i)/NUM_COLORS)

而且，它没有覆盖gist_rainbow地图中的颜色范围，我必须重新定义一个地图.

Moreover, it does not cover the range of colours in the gist_rainbow map, I have to redefine a map.

也许生成器不是执行此操作的最佳方式，如果是这样，可接受的方式是什么?

Maybe a generator is not the best way to do this, if so what is the accepted way?

推荐答案

要为特定颜色表中的颜色编制索引，可以使用:

To index colors from a specific colormap you can use:

import pylab
NUM_COLORS = 22

cm = pylab.get_cmap('gist_rainbow')
for i in range(NUM_COLORS):
    color = cm(1.*i/NUM_COLORS)  # color will now be an RGBA tuple

# or if you really want a generator:
cgen = (cm(1.*i/NUM_COLORS) for i in range(NUM_COLORS))

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