matplotlib 循环为每个类别制作子图 [英] matplotlib loop make subplot for each category
问题描述
我正在尝试编写一个循环,该循环将使图形包含25个子图,每个国家1个.我的代码制作了一个包含 25 个子图的图,但这些图是空的.我可以更改什么才能使数据显示在图表中?
I am trying to write a loop that will make a figure with 25 subplots, 1 for each country. My code makes a figure with 25 subplots, but the plots are empty. What can I change to make the data appear in the graphs?
fig = plt.figure()
for c,num in zip(countries, xrange(1,26)):
df0=df[df['Country']==c]
ax = fig.add_subplot(5,5,num)
ax.plot(x=df0['Date'], y=df0[['y1','y2','y3','y4']], title=c)
fig.show()
推荐答案
您在matplotlib绘图函数和pandas绘图包装器之间感到困惑.
您遇到的问题是 ax.plot
没有任何 x
或 y
参数.
You got confused between the matplotlib plotting function and the pandas plotting wrapper.
The problem you have is that ax.plot
does not have any x
or y
argument.
在这种情况下,请像 ax.plot(df0 ['Date'],df0 [['y1','y2']])
一样调用它,而无需 x
、y
和 title
.可能单独设置标题.示例:
In that case, call it like ax.plot(df0['Date'], df0[['y1','y2']])
, without x
, y
and title
. Possibly set the title separately.
Example:
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
countries = np.random.choice(list("ABCDE"),size=25)
df = pd.DataFrame({"Date" : range(200),
'Country' : np.repeat(countries,8),
'y1' : np.random.rand(200),
'y2' : np.random.rand(200)})
fig = plt.figure()
for c,num in zip(countries, xrange(1,26)):
df0=df[df['Country']==c]
ax = fig.add_subplot(5,5,num)
ax.plot(df0['Date'], df0[['y1','y2']])
ax.set_title(c)
plt.tight_layout()
plt.show()
在这种情况下,通过 df0.plot(x ="Date",y = ['y1','y2'])
绘制数据.
In this case plot your data via df0.plot(x="Date",y =['y1','y2'])
.
示例:
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
countries = np.random.choice(list("ABCDE"),size=25)
df = pd.DataFrame({"Date" : range(200),
'Country' : np.repeat(countries,8),
'y1' : np.random.rand(200),
'y2' : np.random.rand(200)})
fig = plt.figure()
for c,num in zip(countries, xrange(1,26)):
df0=df[df['Country']==c]
ax = fig.add_subplot(5,5,num)
df0.plot(x="Date",y =['y1','y2'], title=c, ax=ax, legend=False)
plt.tight_layout()
plt.show()
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