matplotlib yticks中的值错误 [英] Wrong value in matplotlib yticks

问题描述

我正在尝试从pandas数据框进行绘制，而matplotlib在yticks中显示了错误的值

I'm trying to plot from pandas dataframe and matplotlib show wrong value in yticks

高度数据:
2014-08-08 06:00:00 2609.4942014-08-08 05:45:00 2609.5502014-08-08 05:30:00 2609.6052014-08-08 05:15:00 2609.6582014-08-08 05:00:00 2609.7032014-08-08 04:45:00 2609.7412014-08-08 04:30:00 2609.7692014-08-08 04:15:00 2609.7872014-08-08 04:00:00 2609.7992014-08-08 03:45:00 2609.802

代码:

 import pandas as pd
 df = pd.Dataframe('mydata')
 df.plot()

绘制图形的链接:http://bayanbox.ir/id/7161086291332750314?view

我不知道是否必须在yticks中放置"2609.703"之类的值，而不是图形中显示的值

I don't know have to put value like '2609.703' in yticks instead of what shown in graph

推荐答案

它没有显示不正确的刻度，它只是显示相对于偏移值的内容(注意 y 轴顶部的文本).默认情况下，当您显示大数字且它们之间的差异很小时，就会发生这种情况.

It's not showing incorrect ticks, it's just displaying things relative to an offset value (notice the text at the top of the y-axis). By default, this happens whenever you're displaying large number with very little difference between them.

使用 ax.ticklabel_format(...).在您的情况下，您要指定 useOffset = False .

例如:

import matplotlib.pyplot as plt

data = [2609.494, 2609.55, 2609.605, 2609.658, 2609.703,
        2609.741, 2609.769, 2609.787, 2609.799, 2609.802]

fig, ax = plt.subplots()
ax.plot(data)

ax.ticklabel_format(useOffset=False)

plt.show()

或者，如果您使用的是熊猫 DataFrame 的 plot 方法，则其返回值是axes对象，所以只需:

Or, if you're using the plot method of a Pandas DataFrame, its return value is the axes object, so just:

ax = df.plot()
ax.ticklabel_format(useOffset=False)

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