Arduino的开关打开中继计时器 [英] Arduino Switch to Turn a Relay timer

问题描述

简单地说：我想打开一个继电器30秒，之后我就拨动一个开关

我想在家里做一个百叶窗自动化。

我有一个简单的ON-OFF-ON开关，连接到一个Arduino连接到继电器。

我想，如果我从心拨动开关向下打开继电器＃1为最多30秒。换句话说，继电器接通，当我打开，当计时器达到30秒继电器关闭。

同样我想，如果我从中心开关切换到打开继电器＃2，精确至30秒。

当我切换回中心，我想计时器复位。

我无法弄清楚如何。谁能帮助？

我一直在尝试使用elapsedMillis库这一点，这是一个很好的图书馆，可以帮助我避免使用延迟：
http://playground.arduino.cc/$c$c/ElapsedMillis

不过，即使我可以工作继电器没有在30秒的限制，我无法弄清楚code结束继电器工作。这是我目前的code：

 的#include＆LT; elapsedMillis.h＆GT;
    ＃定义RELAY_ON 0
    ＃定义RELAY_OFF 1    ＃定义RELAY1_TURNS_ON_BLINDS 5
    ＃定义RELAY2_SHUTS_DOWN_BLINDS 6    ＃定义shutswitch A0
    OpenSwitch的的#define A1    布尔LocalCommandToOpen;
    布尔LocalCommandToShut;    无效设置（）//////// SETUP ////////
    {
    digitalWrite（RELAY1_TURNS_ON_BLINDS，RELAY_OFF）;
     digitalWrite（RELAY2_SHUTS_DOWN_BLINDS，RELAY_OFF）;     pinMode（RELAY1_TURNS_ON_BLINDS，OUTPUT）;
     pinMode（RELAY2_SHUTS_DOWN_BLINDS，OUTPUT）;     pinMode（shutswitch，输入）;
     pinMode（OpenSwitch的，输入）;
        } ////建立  无效循环（）{/////// LOOP
         如果（digitalRead（shutswitch）== 1）
     {
       LocalCommandToOpen = 1;
     }
     其他
     {
       LocalCommandToOpen = 0;
     }      如果（digitalRead（OpenSwitch的）== 1）
     {
       LocalCommandToShut = 1;
     }
     其他
     {
       LocalCommandToShut = 0;
     }    unsigned int类型CloseInterval = 14000;
     elapsedMillis timeElapsedSinceCloseButtonPush = 0;
     unsigned int类型OpenInterval = 14000;
     elapsedMillis timeElapsedSinceOpenButtonPush = 0;     //手动开关操作     如果（LocalCommandToShut == 1）
     {
       digitalWrite（RELAY1_TURNS_ON_BLINDS，RELAY_OFF）;
       digitalWrite（RELAY2_SHUTS_DOWN_BLINDS，RELAY_ON）;
     }
     其他
     {
       digitalWrite（RELAY2_SHUTS_DOWN_BLINDS，RELAY_OFF）;
     }    // MANUEL DUGME ILE ACMA
     如果（LocalCommandToOpen == 1）
     {
       digitalWrite（RELAY2_SHUTS_DOWN_BLINDS，RELAY_OFF）;
       digitalWrite（RELAY1_TURNS_ON_BLINDS，RELAY_ON）;
     }
     其他
     {
       digitalWrite（RELAY1_TURNS_ON_BLINDS，RELAY_OFF）;
     }     延迟（500）;    } ///////////////// LOOP /////////////////////////////// /////
 

解决方案

您可以使用一个状态机;这使得事情变得更简单效仿。

类似于：

Arduino的开关打开中继计时器

状态机的一个很好的讨论是在这里：

<一个href=\"https://stackoverflow.com/questions/28356569/complicated-state-transitions-best-practices\">Complicated状态转换：最佳实践

Briefly: I would like to turn on a relay for 30 seconds, after I toggle a switch on.

I'm trying to do a blinds automation at home.

I have a simple ON-OFF-ON switch, attached to an Arduino connected to Relays.

I want to turn on Relay#1 for a maximum of 30 seconds if I toggle the switch down from center. In other words, relay turns on when I switch, and when timer reaches 30 seconds relay turns off.

similarly I want to turn on Relay#2 for exactly 30 seconds if I toggle the switch up from center

And when I switch back to center, I would like the timer to reset.

I could not figure out how. Could anyone help?

I have been trying to use elapsedMillis library for this, which is a nice library that helps me avoid using Delays: http://playground.arduino.cc/Code/ElapsedMillis

However even though I could work the relays without the 30 second limitation, I couldn't figure out the code to end working of the relays. Here is my current code:

      #include <elapsedMillis.h>
    #define RELAY_ON 0
    #define RELAY_OFF 1

    #define RELAY1_TURNS_ON_BLINDS  5
    #define RELAY2_SHUTS_DOWN_BLINDS 6

    #define shutswitch A0
    #define openswitch A1

    bool LocalCommandToOpen;
    bool LocalCommandToShut;

    void setup() ////////SETUP////////
    {
    digitalWrite(RELAY1_TURNS_ON_BLINDS, RELAY_OFF);
     digitalWrite(RELAY2_SHUTS_DOWN_BLINDS, RELAY_OFF);

     pinMode(RELAY1_TURNS_ON_BLINDS, OUTPUT);
     pinMode(RELAY2_SHUTS_DOWN_BLINDS, OUTPUT);

     pinMode(shutswitch, INPUT);
     pinMode(openswitch, INPUT);
        } ////SETUP

  void loop() { ///////LOOP
         if (digitalRead(shutswitch) == 1)
     {
       LocalCommandToOpen = 1;
     }
     else
     {
       LocalCommandToOpen = 0;
     }

      if ( digitalRead(openswitch) == 1)
     {
       LocalCommandToShut = 1;
     }
     else
     {
       LocalCommandToShut = 0;
     }

    unsigned int CloseInterval = 14000;
     elapsedMillis timeElapsedSinceCloseButtonPush = 0;
     unsigned int OpenInterval = 14000;
     elapsedMillis timeElapsedSinceOpenButtonPush = 0;



     //MANUAL SWITCH OPERATION

     if ( LocalCommandToShut == 1 )
     {
       digitalWrite(RELAY1_TURNS_ON_BLINDS, RELAY_OFF);
       digitalWrite(RELAY2_SHUTS_DOWN_BLINDS, RELAY_ON);
     }
     else
     {
       digitalWrite(RELAY2_SHUTS_DOWN_BLINDS, RELAY_OFF);
     }

    //MANUEL DUGME ILE ACMA
     if ( LocalCommandToOpen == 1)
     {
       digitalWrite(RELAY2_SHUTS_DOWN_BLINDS, RELAY_OFF);
       digitalWrite(RELAY1_TURNS_ON_BLINDS, RELAY_ON);
     }
     else
     {
       digitalWrite(RELAY1_TURNS_ON_BLINDS, RELAY_OFF);
     }

     delay(500);

    } /////////////////LOOP////////////////////////////////////

解决方案

You might use a state machine; this makes things a bit easier to follow.

Similar to:

Arduino Switch to Turn a Relay timer

A nice discussion of state machines is here:

Complicated state transitions: best practices

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