Tkinter GUI 问题 [英] Tkinter GUI problems

问题描述

我正在研究一个 项目，但进展并不顺利.
这段代码:

from tkinter import *定义新文件():new = Label(root, text="关于\n")定义打开文件():openf = Label(root, text="关于\n")定义关于():about = Label(root, text="关于\n")根 = Tk()菜单 = 菜单(根)root.config(菜单=菜单)文件菜单 = 菜单(菜单)menu.add_cascade(标签=文件"，菜单=文件菜单)filemenu.add_command(label="New", command=NewFile)filemenu.add_command(label="Open...", command=OpenFile)filemenu.add_separator()filemenu.add_command(label="Exit", command=root.quit)帮助菜单 = 菜单(菜单)menu.add_cascade(label="Help", menu=helpmenu)helpmenu.add_command(label="About...", command=About)body = Label(root, text="")主循环()

不符合我的需要.
当您单击 file > 时，它应该会写入 certant 消息.新建, file >打开和help>关于.

<块引用>

它什么都不做

我怎样才能让它做我想要的?

解决方案

from Tkinter import *根 = Tk()菜单 = 菜单(根)root.config(菜单=菜单)文件菜单 = 菜单(菜单)my_label = Label(root, text="选择菜单")my_label.place(x=10,y=10)def my_command(查询):my_label.config(文本=查询)menu.add_cascade(标签=文件"，菜单=文件菜单)filemenu.add_command(label="New", command=lambda x = "New":my_command(x))filemenu.add_command(label="Open...", command=lambda x = "Open...":my_command(x))filemenu.add_separator()filemenu.add_command(label="Exit", command=root.destroy)帮助菜单 = 菜单(菜单)menu.add_cascade(label="Help", menu=helpmenu)helpmenu.add_command(label="About...", command=lambda x = "About...":my_command(x))body = Label(root, text="")主循环()

@Lafexlos 是正确的.您可以在 GUI 设计中使用所有 python 类型(list、dict、var 等...)，最重要的一点 如何管理所有 GUI 元素，所以都需要一个可访问状态.

不要破坏任何GUI元素，更改并重用它.

不要在mainloop中包含任何外部命令(如:文件、网络等)

所有 GUI 应用程序都需要 3 个临界区:INIT >>构建 >>RUN 否则你会很痛苦.

使用 GUI 元素 text 作为 variable，当然如果所有元素都可以访问！

我希望有帮助并接受@Lafexlos 不是我的回答！此代码适用于 Python2.7

im working on a project but its not going so well.
this code:

from tkinter import *

def NewFile():
    new = Label(root, text="about \n")
def OpenFile():
    openf = Label(root, text="about \n")
def About():
    about = Label(root, text="about \n")

root = Tk()
menu = Menu(root)
root.config(menu=menu)
filemenu = Menu(menu)
menu.add_cascade(label="File", menu=filemenu)
filemenu.add_command(label="New", command=NewFile)
filemenu.add_command(label="Open...", command=OpenFile)
filemenu.add_separator()
filemenu.add_command(label="Exit", command=root.quit)

helpmenu = Menu(menu)
menu.add_cascade(label="Help", menu=helpmenu)
helpmenu.add_command(label="About...", command=About)
body = Label(root, text="")
mainloop()

Doesnt work how I need it.
its suposed to write certant messages when you click file > new, file > open and help > about.

IT DOES NOTHING

how can I make it do what I want?

解决方案

from Tkinter import *



root = Tk()
menu = Menu(root)
root.config(menu=menu)
filemenu = Menu(menu)
my_label = Label(root, text="Select Menu")
my_label.place(x=10,y=10)

def my_command(query):
    my_label.config(text=query)

menu.add_cascade(label="File", menu=filemenu)
filemenu.add_command(label="New", command=lambda x = "New":my_command(x))
filemenu.add_command(label="Open...", command=lambda x = "Open...":my_command(x))
filemenu.add_separator()
filemenu.add_command(label="Exit", command=root.destroy)

helpmenu = Menu(menu)
menu.add_cascade(label="Help", menu=helpmenu)
helpmenu.add_command(label="About...", command=lambda x = "About...":my_command(x))
body = Label(root, text="")
mainloop()

@Lafexlos is correct. You can use all python types(list,dict,var and more...) on GUI design, most important point how to manage all GUI elements, so all need an accessible status.

Don't destroy any GUI element, change and reuse it.

Don't include any external command to mainloop(like:file,network, etc.)

All GUI application required 3 critical section : INIT >> BUILD >> RUN Otherwise you got a lot painful.

Use GUI elements text as variable, of-course if all element is accesible !

I hope helpful and accept @Lafexlos answer not my ! This code work on Python2.7

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