执行C模块的二进制字符串 [英] Execute binary string of C module

问题描述

有人用 Nuitka 为 python 创建了一个 C 模块.(原始的 Python 代码不可用，该模块已经编译 - 所以它是一个机器二进制文件.)我想在另一个工具中使用该代码，该工具只除了 Python 文件.所以我想将 C 代码包含到 Python 中.

Someone created a C module for python with Nuitka. (The original Python code is not available, the module is already compiled - so it is a machine binary file.) I would like to use the code within another tool, which only excepts Python files. So I would like to include the C code into Python.

更具体地说:到目前为止，我有文件 thatmodule.pyi 和一个 thatmodule.so.我可以通过在 mymodule.py 中运行 import thatmodule 将它们包含到我当前的 Python 代码中.现在我只想要一个 Python 文件 mymodule.py.

To get more specific: So far I have the files thatmodule.pyi and a thatmodule.so. I can include them into my current Python code simply by running import thatmodule inside mymodule.py. Now I only want one single Python file mymodule.py.

我目前的想法是将 thatmodule.pyi 中的代码复制到 mymodule.py 的开头，并将 thatmodule.so 转换为带有

My current idea is to copy the code from thatmodule.pyi to the beginning of mymodule.py and to convert thatmodule.so to a binary string with

with open('thatmodule.so', mode='rb') as file:
    fileContent = file.read()

... missing ... how to convert fileContent to b'string'...

并将这个二进制字符串放入mymodule.py.然后我必须从我的 python 模块 mymodule.py 中执行这个二进制字符串.我该怎么做?

and put this binary string into mymodule.py. And then I have to execute this binary string from within my python module mymodule.py. How can I do this?

推荐答案

如果您有描述 thatmodule.so 函数的文档，您可以使用以下内容:

If you have a documentation, which describes functions for thatmodule.so , you can use the following:

import ctypes
mylib = ctypes.CDLL("thatmodule.so")

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