用于聚合 $map 的 SpringData mongoDB API [英] SpringData mongoDB API for Aggregation $map
本文介绍了用于聚合 $map 的 SpringData mongoDB API的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
以下是我的本机 MongoDB 查询,以下是 SpringData Mongo API 等效项.我对在 SpringData Mongo API 中的 $project 中使用 $map 感到震惊.感谢您帮助我完成 API 转换
Following is my Native MongoDB query and below is the SpringData Mongo API equivalent. I am getting struck on using $map in $project in SpringData Mongo API. Appreciate your help on completing my conversion to API
db.users.aggregate([
{ $match: {$and : [{userType:"200"} },
{ $unwind: "$userOrgMap" },
{
$lookup:
{
from: "users",
localField: "userOrgMap.createdbyuser",
foreignField: "_id",
as: "created_by"
}
},
{$project:{
_id:"$_id",
login:"$login",
firstName:"$firstName",
lastName:"$lastName",
email:"$email",
deactivateFlag:"$deactivateFlag",
createdOn:"$createdOn",
createdBy:{
"$map": {
"input": "$created_by",
"as": "u",
"in": {
"name": { "$concat" : [ "$$u.firstName", " ", "$$u.lastName" ] },
}
}
}
}
},
{ $sort : { createdBy : 1} }
])
Spring 查询
Aggregation aggregation = newAggregation(
Aggregation.match(Criteria.where("userType").is(userType)),
Aggregation.unwind("userOrgMap"),
Aggregation.lookup("users", "userOrgMap.createdbyuser", "_id", "created_by"),
Aggregation.project("userId","login","firstName","lastName","email","deactivateFlag","createdOn")
);
推荐答案
你可以试试下面的$map
聚合.
You can try below $map
aggregation.
project().and(mapItemsOf("created_by").
as("u").
andApply(new AggregationExpression() {
@Override
public DBObject toDbObject(AggregationOperationContext aggregationOperationContext) {
return new BasicDBObject("name", StringOperators.valueOf("u.firstName").concat(" ").concatValueOf("u.lastName").toDbObject(aggregationOperationContext));
}
}))
.as("createdBy");
使用$let
表达式
project().and(VariableOperators.Let.define(VariableOperators.Let.ExpressionVariable.newVariable("u").forExpression(ArrayOperators.arrayOf("created_by").elementAt(0))).
andApply(new AggregationExpression() {
@Override
public DBObject toDbObject(AggregationOperationContext aggregationOperationContext) {
return new BasicDBObject("name", StringOperators.valueOf("u.firstName").concat(" ").concatValueOf("u.lastName").toDbObject(aggregationOperationContext));
}
}))
.as("createdBy");
使用 lambda 和静态导入.
Use lambda and static imports.
import static org.springframework.data.mongodb.core.aggregation.ArrayOperators.arrayOf;
import static org.springframework.data.mongodb.core.aggregation.StringOperators.valueOf;
import static org.springframework.data.mongodb.core.aggregation.VariableOperators.Let.ExpressionVariable.*;
import static org.springframework.data.mongodb.core.aggregation.VariableOperators.Let.define;
import static org.springframework.data.mongodb.core.aggregation.VariableOperators.mapItemsOf;
project().and(mapItemsOf("created_by").
as("u").
andApply(aggregationOperationContext -> new BasicDBObject("name", valueOf("u.firstName").concat(" ").concatValueOf("u.lastName").toDbObject(aggregationOperationContext))))
.as("createdBy");
project().and(define(newVariable("u").forExpression(arrayOf("created_by").elementAt(0))).
andApply(aggregationOperationContext -> new BasicDBObject("name", valueOf("u.firstName").concat(" ").concatValueOf("u.lastName").toDbObject(aggregationOperationContext))))
.as("createdBy");
这篇关于用于聚合 $map 的 SpringData mongoDB API的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文