Mule 负载属性值来自流变量 [英] Mule load property value from flow Variable

问题描述

我有一个场景，我需要从属性文件中获取值，而我需要获取的值将来自变量.

I have a scenario where i need to get the value from the property file and the values which i need to get will be from a variable.

我的道具文件

org1 =active
org1_oracle_user = blah
org1_oracle_password = blahblah
org2 =active
org2_oracle_user = blah2
org2_oracle_password = blah2blah2
org3 = Active
org3_oracle_user = blah3
org3_oracle_password = blah3blah3

现在我通过一些输入获取组织的价值，并且我能够保存到一些变量中.

Now i'm getting the value of the org through some input and i was able to save into some variable.

<set-variable variableName="org_name" value="org1" doc:name="OrgNameVariable" />

此外，我还可以通过 dataweave 获取该组织是否处于活动状态

Also i'm able to get the status of that org as active or not through dataweave

<set-variable variableName="orgTypeStatus" value="#[dw('p(flowVars.org_name)')]" doc:name="orgTypeStatusVariable" />

我能够检索该值是否处于活动状态

I was able to retrieve the value as active or not

但是现在如何将其他键值附加到流变量 org_name获取他们的用户名和密码

But now how do I append the other key values to flow variable org_name to get thier user and password

 <set-variable variableName="m_user" value="#[dw('p(flowVars.org_name.concat('_oracle_user'))')]" doc:name="user"/>

上面的代码不起作用，它说表达式执行失败.

The above code is not working it says execution of expression fails.

我给出了一个示例，因为还有其他基于组织名称的道具，我无法对其进行硬编码

I have give a sample example as there are other props based on the org name and I cant hard code it

推荐答案

你能试试这个表达吗:-

Can you try this expression:-

#[dw('p(flowVars.org_name ++ "_oracle_user")')]

因此，您需要在表达式中对 "" 进行转义，因此您在 XML 配置中的变量将如下所示:-

So, you need to escape "" in the expression and so your variable in XML config will be as follows:-

<set-variable variableName="m_user" value="#[dw('p(flowVars.org_name ++ &quot;_oracle_user&quot;)')]" doc:name="user"/>

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