传递多个参数的回调函数（使用PHP 5.2） [英] Passing more than one argument to a callback function (using PHP 5.2)

问题描述

我正在写一个内容管理系统。该页面的管理进入内容页面，当他进入由特殊字符包围一个数字，它是由观众的屏幕上的一个数据库条目取代解析时。要在解析做到这一点，我使用preg_replace_callback（）。但是，我无法将数据库连接变量传递到回调函数，所以它不会起作用。作为一个短期的解决办法，我只是试图让数据库连接一个全局变量在这一个实例，并使用它的方式，但是这不过是一个草率的组装机，为长期不是一个好主意。

I'm writing a content management system. The page admin enters content for a page and, when he enters a number surrounded by special characters, it's replaced by a database entry on the viewer's screen when parsed. To accomplish this in the parsing, I'm using preg_replace_callback(). However, I can't pass my database connection variable into the callback function, so it won't work. As a short-term workaround I'm just trying to make the database connection a global variable in this one instance and use it that way, but this is nothing but a sloppy kludge and not a good idea for the long-term.

有谁知道如何解决我的问题，甚至是不同的，在做什么，我想要做的更好的办法？

Does anyone know how to solve my problem or even a different, better way of doing what I'm trying to do?

推荐答案

您必须创建一个函数/方法包装它。

You have to create a function/method that wraps it.

class PregCallbackWrap {
    private $dbcon;
    function __construct($dbcon) { $this->dbcon = $dbcon; }
    function callback(array $matches) {
        /* implementation of your callback here. You can use $this->dbcon */
    }
}
$dbcon = /* ... */
preg_replace_callback('/PATTERN/',
    array(new PregCallbackWrap($dbcon), 'callback'), $subject,);

在PHP 5.3，你可以简单地做：

In PHP 5.3, you be able to simply do:

$dbcon = /* ... */
preg_replace_callback('/PATTERN/',
    function (array $matches) use ($dbcon) {
        /* implementation here */
    },
    $subject
);

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