Perl 错误:线程无法启动:共享标量的值无效 [英] Perl Error: thread failed to start: Invalid value for shared scalar

问题描述

尝试运行我的测试代码时出现以下错误:

I get the following error when trying to run my test code:

线程无法启动:./threaded_test.pl 第 47 行的共享标量值无效.

第 47 行是:%hoh = hoh(@new_array);

我的观察:

• 如果我删除了第 47 行和其他引用 %hoh 的行，那么脚本运行时不会出错
• 我可以创建一个新的散列 %new_hash = (itchy => "Scratchy"); 没有错误，但是当我尝试从另一个子节点返回"一个散列时(第 47 行)，它导致上述错误.

• If I remove line 47 and other lines referencing %hoh, then the script runs without errors
• I can create a new hash %new_hash = (itchy => "Scratchy"); without errors, but when I try to "return" a hash from another sub (line 47), it results in the error above.

不幸的是，我无法使用输入/输出队列，因为我使用的 Thread::Queue 版本太旧(并且安装在我无法控制的系统上)并且不支持 hash 和 hash-ref 类型通过队列返回(根据 this).显然，我的版本只支持通过队列返回的字符串.

Unfortunately, I cannot use a in/out Queue because the version of Thread::Queue that I use is too old (and installed on a system I have no control over) and doesn't support hash and hash-ref types to be returned via a Queue (according to this). Apparently, my version only support strings to be returned via queues.

有没有办法成功做到这一点:$hash{$string}{"jc"} = \%hoh;

Is there a way to successfully do this: $hash{$string}{"jc"} = \%hoh;

#!/usr/bin/perl
use strict;
use warnings;
use threads;
use Thread::Queue;
use constant NUM_WORKERS => 10;

my @out_array : shared = ();
main();

sub main
{
    my @results = test1();
    foreach my $item (@results) {
        print "item: $item\n";
    }
}

sub test1
{
    my $my_queue = Thread::Queue->new();
    foreach (1..NUM_WORKERS) {
        async {
            while (my $job = $my_queue->dequeue()) {
                test2($job);
            }
        };
    }
    my @sentiments = ("Axe Murderer", "Mauler", "Babyface", "Dragon");
    $my_queue->enqueue(@sentiments);
    $my_queue->enqueue(undef) for 1..NUM_WORKERS;
    $_->join() for threads->list();
    my @return_array = @out_array;
    return @return_array;   
}

sub test2
{
    my $string = $_[0];
    my %hash : shared;
    my @new_array : shared;
    my %new_hash : shared;
    my %hoh : shared;
    @new_array = ("tom", "jerry");
    %new_hash = (itchy => "Scratchy");
    %hoh = hoh(@new_array);
    my %anon : shared;

    $hash{$string} = \%anon;    
    $hash{$string}{"Grenade"} = \@new_array;
    $hash{$string}{"Pipe bomb"} = \%new_hash;
    $hash{$string}{"jc"} = \%hoh;
    push @out_array, \%hash;
    return;
}

sub hoh
{
    my %hoh;
    foreach my $item (@_) {
        $hoh{"jeepers"}{"creepers"} = $item;
    }
    return %hoh;
}

推荐答案

问题在于您试图存储对共享变量中未共享的内容的引用.您需要使用前面提到的share，或者您需要序列化数据结构.

The problem is that your trying to store a reference to something that isn't shared in a shared variable. You need to use share as previously mentioned, or you need to serialise the data structure.

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