在 MySQL 中使用 sequelize 自动增加 id [英] Auto increment id with sequelize in MySQL

问题描述

我在 NodeJS 中有以下模型，带有 sequelize 和 MySQL 数据库:

I have the following model in NodeJS with sequelize and a MySQL database:

var Sequelize = require('sequelize');
var User = sequelize.define('user', {        
        id: {
            type: Sequelize.INTEGER,
            autoIncrement: true,
            primaryKey: true
        },
        ...
};

我正在尝试使用以下代码将新用户添加到我的数据库中:

I am trying to add a new user to my databse with the below code:

sequelize.transaction().then(function(t) {
        User.create({/* User data without id */}, {
            transaction: t
        }).then(function() {
            t.commit();
        }).catch(function(error) {
            t.rollback();
        });
    });

在那之后，我收到下一个错误:

After that, I am getting the next error:

Executing (47f19f7b-a02d-4d72-ba7e-d5045520fffb): START TRANSACTION;
Executing (47f19f7b-a02d-4d72-ba7e-d5045520fffb): SET SESSION TRANSACTION ISOLATION LEVEL REPEATABLE READ;
Executing (47f19f7b-a02d-4d72-ba7e-d5045520fffb): SET autocommit = 1;
Executing (47f19f7b-a02d-4d72-ba7e-d5045520fffb): INSERT INTO `user` (`id`, /* next fields */) VALUES (DEFAULT, /* next values */);
Executing (47f19f7b-a02d-4d72-ba7e-d5045520fffb): ROLLBACK;

和错误信息:

[SequelizeDatabaseError: ER_NO_DEFAULT_FOR_FIELD: Field 'id' doesn't have a default value]
  name: 'SequelizeDatabaseError',
  message: 'ER_NO_DEFAULT_FOR_FIELD: Field \'id\' doesn\'t have a default value'

但是，如果我手动设置 id 值，它就可以工作.似乎 sequelize 试图在 id 字段中设置一个默认值，而不是设置一个自动增量整数.我也在我的数据库中将此字段定义为 autoIncrement.

However, if I manually set the id value, it works. It seems sequelize is trying to set a default value in the id field, instead setting an autoincrement integer. I have defined this field as autoIncrement in my database too.

我怎么能做这个插入?我必须手动设置 id 吗?

How could I do this insertion? Do I have to set the id manually?

编辑

这是我的表定义:

CREATE TABLE `user` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `uid` varchar(9) NOT NULL,
  `name` varchar(20) NOT NULL,
  `email` varchar(30) DEFAULT NULL,
  `birthdate` date NOT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `uid_UNIQUE` (`uid`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

推荐答案

你必须确保你根本没有发送 id 键.

You must be sure you're not even sending the id key at all.

我做了一个快速的最小测试，它似乎工作得很好:

I have done a quick minimal test and it seemed to work great:

var Sequelize = require('sequelize');
var sequelize = new Sequelize('cake3', 'root', 'root', {
    define: {
        timestamps: false
    },
});
var User = sequelize.define('user1', {        
        id: {
            type: Sequelize.INTEGER,
            autoIncrement: true,
            primaryKey: true
        },
        name: {
            type: Sequelize.STRING
        }
});

sequelize.transaction().then(function(t) {
    User.create({name:'test'}, {
        transaction: t
    }).then(function() {
        t.commit();
    }).catch(function(error) {
        console.log(error);
        t.rollback();
    });
});

表转储:

CREATE TABLE `user1s` (
  `id` int(11) NOT NULL,
  `name` varchar(20) NOT NULL
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=utf8;
ALTER TABLE `user1s`
  ADD PRIMARY KEY (`id`);
ALTER TABLE `user1s`
  MODIFY `id` int(11) NOT NULL AUTO_INCREMENT,AUTO_INCREMENT=1;

这篇关于在 MySQL 中使用 sequelize 自动增加 id的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！