如何使用 commit() 查找记录插入到 mysql [英] how to find record insert to mysql using commit()

问题描述

抱歉这个初学者的问题，我不是 PHP 开发人员，但现在我正在努力学习.

Sorry for this beginners question and i'm not a PHP developer, but now i'm trying to learn it.

我想在 MySQL 数据库中添加记录，我正在使用事务锁.

i want to add record in MySQL data base and i'm using transactions lock.

我的代码如下.

$SqlQuery="INSERT INTO tab_photo VALUES('$PhotoID','$ProjectId','$Day','$barCode','$photoName','$PhotoXml')";

$waiting = true;
while($waiting) {
    try {
        // save border data
        $stmt = $conn->prepare($SqlQuery);
        $conn->beginTransaction();
        $stmt->execute();
        sleep(1);

        $x=$conn->commit();
        echo "x value-".$x;

        echo "Success";
        $waiting = false;
    }
    catch (PDOException $e){
        echo "Failled :".$PhotoID."-".$PhotoID;
        if(stripos($e->getMessage(), 'DATABASE IS LOCKED') !== false) {
            // This should be specific to SQLite, sleep for 0.25 seconds
            // and try again.  We do have to commit the open transaction first though
            $conn->commit();
            usleep(250000);
        } else {
            $conn->rollBack();
            throw $e;
        }
    }
}

在这里作为它给出的输出，

in here as output it gives,

x value-1 Success

但实际上这条记录并没有添加到数据库中.

but actually this record doesn't add to the database.

我的问题:

1. 即使提交成功(输出 1)它怎么不添加到数据库中?
2. 如何检查记录是否添加到数据库中?(有没有什么办法不用写select语句就可以找到它?

推荐答案

据我所知，您希望在语句执行失败时会抛出 PDOException.但正如我所见，在这种情况下，默认情况下不会抛出异常.在此处

As I understand, you expect that PDOException will be thrown when statement is failed to execute. But as I can see, exception is not thrown by default in such cases. See how you can change that here

假设在你的情况下你应该有一个这样的代码:

Suppose in your case you should have a code like this:

$conn = new PDO($connection_string); 
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); // this will force PDO to throw exception when SQL statement fails instead of simply setting an error.

假设这对您有用.

请注意不要使用

$SqlQuery="INSERT INTO tab_photo VALUES('$PhotoID','$ProjectId','$Day','$barCode','$photoName','$PhotoXml')";

相反，您应该使用参数绑定:

Instead of that, you should use parameters binding:

$SqlQuery="INSERT INTO tab_photo VALUES(:PhotoID,:ProjectId,:Day,:barCode,:photoName,:PhotoXml)";
$stmt = $conn->prepare($SqlQuery);
$conn->beginTransaction();
$stmt->execute(array(':PhotoID' => $PhotoID, ':ProjectId' => $ProjectId, ....));
sleep(1);

有关详细信息，请参阅此.

See this for more details.

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