相同的形式，但有输入做其他事情 [英] Same form but have input do something else
本文介绍了相同的形式，但有输入做其他事情的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
刚刚创建了一个changedetails.php"页面，用户可以在其中更改他们的详细信息，例如密码"和电子邮件".它们都工作成功，但我试图允许用户更改他们的电子邮件而不必更改他们的密码.
所以基本上，如果用户只想更改他们的电子邮件，它将在数据库中更新，而无需更改他们的密码.
代码:
Honda | <meta http-equiv="Content-Type" content="text/html; charset=utf-8"/><meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1"><link href='http://fonts.googleapis.com/css?family=Julius+Sans+One' rel='stylesheet' type='text/css'><link href="../css/style.css" rel="stylesheet" type="text/css" media="all"/><?phpsession_start();$username = $_SESSION['sess_user'];echo '<div class="search1"><h2>'.$username.'</h2></div>';如果(isset($_SESSION['sess_user'])){//用户已登录if (isset($_POST['submit'])) {//开始修改密码//检查字段$oldpassword = md5($_POST['oldpassword']);$newpassword = md5($_POST['newpassword']);$email = $_POST['email'];$repeatnewpassword = md5($_POST['repeatnewpassword']);//根据数据库检查密码include('../includes/config.php');$queryget = mysql_query("选择密码从登录WHERE username='$用户名'")或死(更改密码失败")；$row = mysql_fetch_assoc($queryget);$oldpassworddb = $row['password'];//检查密码如果($oldpassword==$oldpassworddb){//检查两个新密码如果($newpassword==$repeatnewpassword){//成功//修改数据库中的密码$querychange = mysql_query("更新登录设置密码='$新密码'WHERE username='$用户名'");$querychange = mysql_query("更新登录设置电子邮件='$电子邮件'WHERE username='$用户名'");die("您的密码已被更改.<br><br>返回");} 别的 {die("<div class='results'>新密码不匹配！</div>");}} 别的 {die("<div class='results'>旧密码不匹配！</div>");}} 别的 {echo "
谢谢！
更新 2:
if ($newpassword != "") {//检查密码如果($oldpassword==$oldpassworddb){//检查两个新密码如果($newpassword==$repeatnewpassword){//成功//修改数据库中的密码$querychange = mysql_query("UPDATE login SET password='$newpassword' WHERE username='$username'");}别的die("<div class='results'>新密码不匹配！</div>");}别的die("<div class='results'>旧密码不匹配！</div>");}}如果 ($email != "") {$querychange = mysql_query("UPDATE login SET email='$email' WHERE username='$username'");die("<div class='successmate'>您的密码已更改.<a href='index2.php'><br><br> Return</a></div>");}}别的{回声" 解决方案
问题是你两个查询紧接着运行，你需要添加一个检查，看看密码是否为空，然后跳过密码查询，如果电子邮件为空则跳过电子邮件查询
if ($newpassword != "") {//检查密码如果($oldpassword==$oldpassworddb){//检查两个新密码如果($newpassword==$repeatnewpassword){//成功//修改数据库中的密码$querychange = mysql_query("UPDATE login SET password='$newpassword' WHERE username='$username'");别的die("<div class='results'>新密码不匹配！</div>");}别的die("<div class='results'>旧密码不匹配！</div>");}}如果 ($email != "") {$querychange = mysql_query("UPDATE login SET email='$email' WHERE username='$username'");die("<div class='successmate'>您的密码已更改.<a href='index2.php'><br><br> Return</a></div>");}完整代码集(OP 要求)
Honda | <meta http-equiv="Content-Type" content="text/html; charset=utf-8"/><meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1"><link href='http://fonts.googleapis.com/css?family=Julius+Sans+One' rel='stylesheet' type='text/css'><link href="../css/style.css" rel="stylesheet" type="text/css" media="all"/><?phpsession_start();$username = $_SESSION['sess_user'];echo '<div class="search1"><h2>'.$username.'</h2></div>';如果(isset($_SESSION['sess_user'])){//用户已登录if (isset($_POST['submit'])) {//开始修改密码//检查字段$oldpassword = md5($_POST['oldpassword']);$newpassword = md5($_POST['newpassword']);$email = $_POST['email'];$repeatnewpassword = md5($_POST['repeatnewpassword']);//根据数据库检查密码include('../includes/config.php');$queryget = mysql_query("SELECT password FROM login WHERE username='$username'")或死(更改密码失败")；$row = mysql_fetch_assoc($queryget);$oldpassworddb = $row['password'];如果($新密码！="){//检查密码如果($oldpassword==$oldpassworddb){//检查两个新密码如果($newpassword==$repeatnewpassword){//成功//修改数据库中的密码$querychange = mysql_query("UPDATE login SET password='$newpassword' WHERE username='$username'");die("您的密码已被更改.<br><br>返回");} 别的 {die("<div class='results'>新密码不匹配！</div>");}} 别的 {die("<div class='results'>旧密码不匹配！</div>");}}如果 ($email != "") {$querychange = mysql_query("UPDATE login SET email='$email' WHERE username='$username'");die("
您的电子邮件已更改.<br><br>返回");}} 别的 {echo "
just created a 'changedetails.php' page where users are able to change their details such as 'password' and 'email'. They all work successful but I am trying to allow a user to change their email without having to change their password as well.
So basically, if a user only wanted to change their email it will update in the DB without having to change their passwords.
Code:
<title>Honda |</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1">
<link href='http://fonts.googleapis.com/css?family=Julius+Sans+One' rel='stylesheet' type='text/css'>
<link href="../css/style.css" rel="stylesheet" type="text/css" media="all" />
<?php
session_start();
$username = $_SESSION['sess_user'];
echo '<div class="search1"><h2>'.$username.'</h2></div>';
if (isset($_SESSION['sess_user'])) {
//user is logged in
if (isset($_POST['submit'])) {
//start changing password
//check fields
$oldpassword = md5($_POST['oldpassword']);
$newpassword = md5($_POST['newpassword']);
$email = $_POST['email'];
$repeatnewpassword = md5($_POST['repeatnewpassword']);
//check password against db
include('../includes/config.php');
$queryget = mysql_query("SELECT password
FROM login
WHERE username='$username'")
or die ("change password failed");
$row = mysql_fetch_assoc($queryget);
$oldpassworddb = $row['password'];
//check passwords
if ($oldpassword==$oldpassworddb) {
//check two new passwords
if ($newpassword==$repeatnewpassword) {
//successs
//change password in db
$querychange = mysql_query("UPDATE login
SET password='$newpassword'
WHERE username='$username'");
$querychange = mysql_query("UPDATE login
SET email='$email'
WHERE username='$username'");
die("<div class='successmate'>
Your password has been changed. <a href='index2.php'>
<br><br> Return</a></div>");
} else {
die("<div class='results'>New password doesn't match!</div>");
}
} else {
die("<div class='results'>Old password doesn't match!</div>");
}
} else {
echo "<form class='search1' action='changepassword.php' method='POST'>";
echo "<label>Old Password:</label> <input type='password' id='password' name='oldpassword'>";
echo "<p><label>New Password:</label> ";
echo "<input type='password' id='password' name='newpassword'>";
echo "<p><label>Repeat New Password:</label> ";
echo "<input type='password' name='repeatnewpassword'><p>";
echo "<label>Email:</label> <input type='email' name='email'>";
echo "<p><input type='submit' name='submit' class='submit' value='submit'>";
echo "<br><br><br><h2><p><a href='index2.php'>Back</a></p></h2></form>";
}
} else {
die ("You must be logged in to change your password");
}
?>
<img src="../images/main.jpg">
Thanks!
UPDATE 2:
if ($newpassword != "") {
//check passwords
if ($oldpassword==$oldpassworddb)
{
//check two new passwords
if ($newpassword==$repeatnewpassword)
{
//successs
//change password in db
$querychange = mysql_query("UPDATE login SET password='$newpassword' WHERE username='$username'");
}
else
die("<div class='results'>New password doesn't match!</div>");
}else
die("<div class='results'>Old password doesn't match!</div>");
}
}
if ($email != "") {
$querychange = mysql_query("UPDATE login SET email='$email' WHERE username='$username'");
die("<div class='successmate'>Your password has been changed. <a href='index2.php'><br><br> Return</a></div>");
}
}
else
{
echo"
<form class='search1' action='changepassword.php' method='POST'>
<label>Current Password:</label> <input type='password' id='password' name='oldpassword'><p>
<label>New Password:</label> <input type='password' id='password' name='newpassword'><p>
<label>Repeat New Password:</label> <input type='password' name='repeatnewpassword'><p>
<label>Email:</label> <input type='email' name='email'><p>
<input type='submit' name='submit' class='submit' value='submit'><br><br><br>
<h2><p><a href='index2.php'>Back</a></p></h2>
</form>
";
}
{else
die ("You must be logged in to change your password");
?>
解决方案
The problem is you are running the 2 queries right after each other, you need to add a check to see if password is blank, then skip password query, if email is blank then skip email query
EDIT:
if ($newpassword != "") {
//check passwords
if ($oldpassword==$oldpassworddb)
{
//check two new passwords
if ($newpassword==$repeatnewpassword)
{
//successs
//change password in db
$querychange = mysql_query("UPDATE login SET password='$newpassword' WHERE username='$username'");
else
die("<div class='results'>New password doesn't match!</div>");
}else
die("<div class='results'>Old password doesn't match!</div>");
}
}
if ($email != "") {
$querychange = mysql_query("UPDATE login SET email='$email' WHERE username='$username'");
die("<div class='successmate'>Your password has been changed. <a href='index2.php'><br><br> Return</a></div>");
}
FULL CODE SET(Requested by OP)
<title>Honda |</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1">
<link href='http://fonts.googleapis.com/css?family=Julius+Sans+One' rel='stylesheet' type='text/css'>
<link href="../css/style.css" rel="stylesheet" type="text/css" media="all" />
<?php
session_start();
$username = $_SESSION['sess_user'];
echo '<div class="search1"><h2>'.$username.'</h2></div>';
if (isset($_SESSION['sess_user'])) {
//user is logged in
if (isset($_POST['submit'])) {
//start changing password
//check fields
$oldpassword = md5($_POST['oldpassword']);
$newpassword = md5($_POST['newpassword']);
$email = $_POST['email'];
$repeatnewpassword = md5($_POST['repeatnewpassword']);
//check password against db
include('../includes/config.php');
$queryget = mysql_query("SELECT password FROM login WHERE username='$username'")
or die ("change password failed");
$row = mysql_fetch_assoc($queryget);
$oldpassworddb = $row['password'];
if ($newpassword != "") {
//check passwords
if ($oldpassword==$oldpassworddb) {
//check two new passwords
if ($newpassword==$repeatnewpassword) {
//successs
//change password in db
$querychange = mysql_query("UPDATE login SET password='$newpassword' WHERE username='$username'");
die("<div class='successmate'>
Your password has been changed. <a href='index2.php'>
<br><br> Return</a></div>");
} else {
die("<div class='results'>New password doesn't match!</div>");
}
} else {
die("<div class='results'>Old password doesn't match!</div>");
}
}
if ($email != "") {
$querychange = mysql_query("UPDATE login SET email='$email' WHERE username='$username'");
die("<div class='successmate'>
Your email been changed. <a href='index2.php'>
<br><br> Return</a></div>");
}
} else {
echo "<form class='search1' action='changepassword.php' method='POST'>";
echo "<label>Old Password:</label> <input type='password' id='password' name='oldpassword'>";
echo "<p><label>New Password:</label> ";
echo "<input type='password' id='password' name='newpassword'>";
echo "<p><label>Repeat New Password:</label> ";
echo "<input type='password' name='repeatnewpassword'><p>";
echo "<label>Email:</label> <input type='email' name='email'>";
echo "<p><input type='submit' name='submit' class='submit' value='submit'>";
echo "<br><br><br><h2><p><a href='index2.php'>Back</a></p></h2></form>";
}
} else {
die ("You must be logged in to change your password");
}
?>
<img src="../images/main.jpg">
这篇关于相同的形式，但有输入做其他事情的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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