Mysql:根据两个查询减去值 [英] Mysql: Subtracting values based on two queries

问题描述

我有以下两个查询.

SELECT 
    account_name,SUM(amount) AS AMOUNT1 
FROM 
    entries 
LEFT JOIN 
    accounts ON accounts.id = entries.accounts_id
WHERE 
    side = 'D' AND op_balance_dc = 'D'
GROUP BY 
    accounts.id

查询结果如下:

查询 1

SELECT 
    account_name,SUM(amount) AS AMOUNT2 
FROM 
    entries 
LEFT JOIN 
    accounts ON accounts.id = entries.accounts_id
WHERE 
    side = 'C' AND op_balance_dc = 'D'
GROUP BY 
    accounts.id

这是第二次查询的结果

查询 2

我不是要显示上述两个查询的结果，我要实现的是从上述查询中获取 account_name、AMOUNT1 和 AMOUNT2，然后从 AMOUNT1- 中减去 Amount2，然后从我的表中添加一个值柱子.

I am not trying to display the results of the above two queries, what I am trying to achieve is get the account_name, AMOUNT1 and AMOUNT2 FROM the above queries and then subtract Amount2 FROM AMOUNT1- and then add a value from my table's column.

示例:

(AMOUNT1-AMOUNT2)+op_balance  //here op_balance is my column name

然后显示account_name和(AMOUNT1-AMOUNT2)+op_balance

你能帮我解决这个问题吗?

Could you please help me with this query?

谢谢:)

如果您需要更多信息，请告诉我.:)

Please let me know if you need anymore information.:)

这是我的表的结构:

• 表名称:账户
• 表名称:条目

谢谢:)

表名:条目(Case-1)

Table Name: entries (Case-1)

  id    trans_id   accounts_id    amount    side
   1      1       12               1000      D
   2      1        1               1000      C
   7      4        1              14000      D
   8      4        2              14000      C

表名:条目(Case-2)

Table Name: entries (Case-2)

  id    trans_id   accounts_id  amount        side
  1           1       12          1000       D
  2           1        1          1000       C

您的代码适用于案例 1，但不适用于案例 2.您在代码中使用了 lentries.accounts_id = entries.accounts_id 这就是为什么因为表中相同的 accounts_id 没有多个值要加入并且您的代码不计算在内case-2 中的值.

Your code will work for the case-1 but not for case-2. You used lentries.accounts_id = entries.accounts_id in your code and that is why since there's no multiple values for the same accounts_id in the table to join and your code is not counting the values in case-2.

但我正在尝试获取所有数据.谢谢:)

But I am trying to get all the data. Thanks :)

推荐答案

这是所有帐户的 EDITED QUERY

Here is the EDITED QUERY for all accounts

select
  a.id,
  a.account_name,
  a.op_balance,
  ifnull(e.AMOUNT1,0) as Amount1,
  ifnull(l.AMOUNT2,0) as Amount2,
  ((ifnull(SUM(e.AMOUNT1),0)-ifnull(l.AMOUNT2,0))+a.op_balance) as Balance
from accounts a
  left join (SELECT
               accounts_id,
               SUM(amount)     AS AMOUNT1
             FROM entries
               LEFT JOIN accounts
                 ON accounts.id = entries.accounts_id
             WHERE entries.side = 'D'
                 AND accounts.op_balance_dc = 'D'
             GROUP BY accounts.id) as e
    on e.accounts_id = a.id
  left join (SELECT
               accounts_id,
               SUM(amount)     AS AMOUNT2
             FROM entries
               LEFT JOIN accounts
                 ON accounts.id = entries.accounts_id
             WHERE side = 'C'
                 AND op_balance_dc = 'D'
             GROUP BY accounts.id) as l
    on l.accounts_id = a.id
group by a.id   

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