MYSQL 中不存在多个以检查行数 [英] Multiple not exists in MYSQL to check count of rows

问题描述

我正在尝试使此查询起作用，这是我的逻辑，我正在尝试选择至少没有以下选项之一的记录:

I am trying to make this query work, here is my logic , I am trying to select record thats there is not at LEAST NOT one of these options:

1). status = Approved AND end_date >now
2). status =Approved AND end_date is NULL
3). status = Pending And end_date is NULL & COUNT(id) =1
4). status =Pending AND end_date >now & COUNT(id) =1
5). status =Pending AND end_date <now & COUNT(id) =1

如何做到这一点，这是我到目前为止我不知道如何在条件 3、4 和 5 中检查 COUNT(id) = 1 的方法?

how to accomplish this , this is what I have so far I am not sure how to check for COUNT(id) = 1 in conditions 3, 4, and 5?

SELECT
    *
FROM
    outreach
WHERE
    NOT EXISTS (
        SELECT
            *
        FROM
            outreach_links
        WHERE
            outreach_links.outreach_id = outreach.id
        AND STATUS = "Approved"
        AND end_date > now()
    )
AND NOT EXISTS (
    SELECT
        *
    FROM
        outreach_links
    WHERE
        outreach_links.outreach_id = outreach.id
    AND STATUS = "Approved"
    AND end_date IS NULL
)
AND NOT EXISTS (
    SELECT
        *
    FROM
        outreach_links
    WHERE
        outreach_links.outreach_id = outreach.id
    AND STATUS = "Pending"
    AND end_date > now()
)
AND NOT EXISTS (
    SELECT
        *
    FROM
        outreach_links
    WHERE
        outreach_links.outreach_id = outreach.id
    AND STATUS = "Pending"
    AND end_date IS NULL
)
AND NOT EXISTS (
    SELECT
        *
    FROM
        outreach_links
    WHERE
        outreach_links.outreach_id = outreach.id
    AND STATUS = "Pending"
    AND end_date < now()
)

推荐答案

select
    o.*,
    SUM(if(ol.status = "Approved" and (ol.end_date > now() or end_date is null), 1, 0)) as cond1,
    SUM(if(ol.status = "Pending" and (ol.end_date != now() or end_date is null), 1, 0)) as cond2
from
    outreach o
left join 
    outreach_links ol on ol.outreach_id = o.id
group by
    o.id
having
    cond1 = 0 and cond2 != 1
;

不确定是否是您要找的，但您可以尝试一下.cond2 != 1 使您的 COUNT(id) = 1 条件(如果 outreach_links 中有多个链接的 id，则 cond2 将大于 1)

Not sure if that's you are looking for, but you can try it. cond2 != 1 makes your COUNT(id) = 1 condition (if there are more than one linked id in outreach_links cond2 will be greater than 1)

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