MySQL 选择查询 ANDed 同一列的多个条件 [英] MySQL select query ANDed multiple condition of same column

问题描述

我有下面的测试表，表中有以下几行.

I have the below test table with the following rows in the table.

table: test_set(id (pk), pid int, fc int, fl int)

pid      fc    fl
1        7     30
1        8     31
1        9     35
2        7     39
2        8     40

现在如果我跑

SELECT pid FROM test_set WHERE fl=30 OR fl=35 GROUP BY pid;
#Result :
pid
---
1

正如预期的那样，但如果我想运行

As expected but if I want to run

SELECT pid FROM test_set WHERE fl=30 AND fl=35 GROUP BY pid;
#Result :
result set (0) # Nothing matched!

这太符合预期了，但我想在这里超出预期.我的逻辑是 fl=30 和 fl=35 都有 pid=1 共同点，即当它们相交时，它们产生 pid=1

This is too as expected but I want to go beyond expectation here. My logic here is that fl=30 and fl=35 both have pid=1 in common i.e. when they are intersected they yeilds pid=1

所以具体来说，我需要具有一个或多个 pid 的 fl 列的多个值的结果.

So to be specific I need the result of multiple values of fl column that have one or more pid in common.

我已经阅读了这个这个并且也有评论.

I have already read this this and commented there too.

推荐答案

关于:

SELECT pid, COUNT(DISTINCT fl) AS count, GROUP_CONCAT(DISTINCT fl) list
FROM test_set
GROUP BY pid HAVING count > 1;

?

输出:

+------+-----------+------------------+
| pid  | count     | list             |
+------+-----------+------------------+
|    1 |         3 | 30,31,35         |
|    2 |         2 | 39,40            |
+------+-----------+------------------+

给定两个 fl 值:

SELECT pid, COUNT(DISTINCT fl) AS count
FROM test_set
WHERE fl IN (30, 35)
GROUP BY pid HAVING count = 2;

输出:

+------+-------+
| pid  | count |
+------+-------+
|    1 |     2 |
+------+-------+

给定三个 fl 值:

SELECT pid, COUNT(DISTINCT fl) AS count
FROM test_set
WHERE fl IN (30, 31, 35)
GROUP BY pid HAVING count = 3;

输出:

+------+-------+
| pid  | count |
+------+-------+
|    1 |     3 |
+------+-------+

pid 和 fl 上有索引是很好的.

It's good to have indexes on pid and fl.

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