从Mysql中获取数据并转换为PHP数组 [英] Get data from Mysql and convert into PHP array

问题描述

我希望在一个我认为一定很简单的问题上得到一些帮助，但我已经被困了一段时间.

I hope to get some help on a problem that I suppose must be simple but I have been stuck for a while.

我有一个简单的 Mysql 表，其中包含 3 个字段(id、customer、sales).我只需要查询这个表并获得一个 php 数组.

I have a simple Mysql table with 3 fields ( id, customer, sales ) . All I need is to query this table and get an php array.

这是我的代码:

$query = "SELECT * FROM mysqltable";    
$result = $mysqli->query($query))

我需要编写一个代码来循环并获取这种格式的数组:

I need to write a code to loop and get an array in this format:

$row=array(0=>"500,200",1=>"500,300",2=>"1000,600",3=>"800,400",4=>"200,500");

所以我可以以

echo json_encode($row);

非常感谢您帮助解决此问题.

Would appreciate any help to solve this.

推荐答案

可以使用mysqli_fetch_all()

You can use mysqli_fetch_all()

    mixed mysqli_result::fetch_all ([ int $resulttype = MYSQLI_NUM ] )

或

    mixed mysqli_fetch_all ( mysqli_result $result [, int $resulttype = MYSQLI_NUM ] )

参考阅读http://php.net/manual/en/mysqli-result.fetch-all.php

还有

<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");

/* check connection */
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

$query = "SELECT Name, CountryCode FROM City ORDER by ID LIMIT 3";
$result = $mysqli->query($query);

while($row = $result->fetch_array())
{
$rows[] = $row;
}

foreach($rows as $row)
{
echo $row['CountryCode'];
}

/* free result set */
$result->close();

/* close connection */
$mysqli->close();
?>

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