如何使用 XdmNode 从标签中读取命名空间? [英] How to read namespace from tags using XdmNode?
问题描述
我希望从 net.sf.saxon.s9api.XdmNode 中存在的一个标签中读取所有命名空间.我可以使用下面的代码读取它们，但由于性能问题，我应该使用现有的 DOM 来解析和读取命名空间.
I wish to read all the namespaces from one tag present in net.sf.saxon.s9api.XdmNode. I'm able to read them using the code below, but due to the performance issue, I should use the existing DOM to parse and read the namespaces.
input.xml
<?xml version="1.0" encoding="utf-8"?>
<?taxonomy-version 2.2.3.0?> <?taxonomy-set-overall-version 2.6.0.0?>
<!--(C) EBA-->
<link:linkbase xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:link="http://www.xbrl.org/2003/linkbase" xmlns:gen="http://xbrl.org/2008/generic" xmlns:label="http://xbrl.org/2008/label" xmlns:formula="http://xbrl.org/2008/formula" xmlns:df="http://xbrl.org/2008/filter/dimension" xmlns:table="http://xbrl.org/2014/table" xmlns:model="http://www.eurofiling.info/xbrl/ext/model" xmlns:eba_dim="http://www.eba.europa.eu/xbrl/crr/dict/dim" xmlns:eba_PL="http://www.eba.europa.eu/xbrl/crr/dict/dom/PL" xmlns:eba_met="http://www.eba.europa.eu/xbrl/crr/dict/met" xmlns:eba_BA="http://www.eba.europa.eu/xbrl/crr/dict/dom/BA" xmlns:eba_MC="http://www.eba.europa.eu/xbrl/crr/dict/dom/MC" xmlns:eba_IM="http://www.eba.europa.eu/xbrl/crr/dict/dom/IM" xmlns:eba_AP="http://www.eba.europa.eu/xbrl/crr/dict/dom/AP" xmlns:eba_TR="http://www.eba.europa.eu/xbrl/crr/dict/dom/TR" xmlns:eba_EC="http://www.eba.europa.eu/xbrl/crr/dict/dom/EC" xmlns:eba_CT="http://www.eba.europa.eu/xbrl/crr/dict/dom/CT" xmlns:eba_GA="http://www.eba.europa.eu/xbrl/crr/dict/dom/GA" xsi:schemaLocation="http://www.xbrl.org/2003/linkbase http://www.xbrl.org/2003/xbrl-linkbase-2003-12-31.xsd http://xbrl.org/2008/generic http://www.xbrl.org/2008/generic-link.xsd http://xbrl.org/2008/label http://www.xbrl.org/2008/generic-label.xsd http://xbrl.org/2008/formula http://www.xbrl.org/2008/formula.xsd http://xbrl.org/2008/filter/dimension http://www.xbrl.org/2008/dimension-filter.xsd http://xbrl.org/2014/table http://www.xbrl.org/2014/table.xsd http://www.eurofiling.info/xbrl/ext/model http://www.eurofiling.info/eu/fr/xbrl/ext/model.xsd">
<link:arcroleRef arcroleURI="http://xbrl.org/arcrole/2014/aspect-node-filter" xlink:type="simple" xlink:href="http://www.xbrl.org/2014/table.xsd#aspect-node-filter" />
<link:arcroleRef arcroleURI="http://xbrl.org/arcrole/2014/breakdown-tree" xlink:type="simple" xlink:href="http://www.xbrl.org/2014/table.xsd#breakdown-tree" />
<link:arcroleRef arcroleURI="http://xbrl.org/arcrole/2014/definition-node-subtree" xlink:type="simple" xlink:href="http://www.xbrl.org/2014/table.xsd#definition-node-subtree" />
<link:arcroleRef arcroleURI="http://xbrl.org/arcrole/2014/table-breakdown" xlink:type="simple" xlink:href="http://www.xbrl.org/2014/table.xsd#table-breakdown" />
<link:roleRef roleURI="http://www.eba.europa.eu/xbrl/crr/role/dict/dom/GA/GA5_1" xlink:type="simple" xlink:href="../../../../../../dict/dom/ga/hier.xsd#eba_GA5_1" />
<link:roleRef roleURI="http://www.eba.europa.eu/xbrl/crr/role/fws/COREP/its-2016-03/2016-11-15/tab/C_09.01.a" xlink:type="simple" xlink:href="c_09.01.a.xsd#role" />
</link:linkbase>
从上面的文件中，我希望从 link:linkbase 标记中读取所有xmlns"属性.
From the above file, I wish to read all the "xmlns" attributes from the link:linkbase tag.
下面的代码片段按预期工作，但达到了性能.
The below code snippet is working as expected but hitting the performance.
代码
private List<Namespace> getNameSpaceListFromFile() throws ValidationException {
List <Namespace>nsList = new ArrayList<Namespace>();
try {
if(inputFile!=null){
BufferedReader bufferedReader = new BufferedReader(new FileReader(inputFile)); //I18NOK:IOE
String line;
StringBuilder stringBuilder = new StringBuilder();
while((line=bufferedReader.readLine())!= null){
stringBuilder.append(line.trim());
}
XMLStreamReader reader = XMLInputFactory.newFactory().createXMLStreamReader(new StringReader(stringBuilder.toString().trim().replaceFirst("^([\\W]+)<","<"))); /*I18NOK:LSM*/ //removing byte order markers by using "^([\\W]+)<","<"
while (reader.hasNext()) {
int event = reader.next();
if (XMLStreamConstants.START_ELEMENT == event) {
if (reader.getNamespaceCount() > 0) {
for (int nsIndex = 0; nsIndex < reader.getNamespaceCount(); nsIndex++) {
System.out.println(reader.getNamespacePrefix(nsIndex).trim()+"\t\t:\t\t"+ reader.getNamespaceURI(nsIndex).trim());
nsList.add(new Namespace(reader.getNamespacePrefix(nsIndex).trim(), reader.getNamespaceURI(nsIndex).trim()));
}
}
}
}
bufferedReader.close();
}
if(nsList.isEmpty()){
return new NamespaceLoader(context).getNsListFromProperties();
}
} catch (Exception e) {
e.printStackTrace();
}
return nsList;
}
我搜索了合适的工作解决方案，但找不到任何解决方案.
I searched for the proper working solution but could not find any.
Iterator <XdmItem> itemList = document.axisIterator(Axis.CHILD);
while(itemList.hasNext()) {
XdmItem item = itemList.next();
System.err.println(item.getStringValue());
}
在上面的代码中，我在 XdmItem 中获得了完整的链接"标签，但找不到读取链接库标签和获取命名空间的方法.
in above code, I get the full "link" tag in XdmItem but could not find a way to read the linkbase tag and fetch the namespaces.
任何形式的帮助将不胜感激.另外，如果需要更多信息，请告诉我.
Any sort of help will be appreciated. also, let me know if any more information is needed.
推荐答案
如果我理解正确，您已经将文档保存为 XdmNode 的一个实例.如果是这种情况，那么您可以使用 s9api 接口来执行 XPath 表达式
If I understand correctly, you already have the document held as an instance of XdmNode. If that's the case then you can use the s9api interface to execute the XPath expression
/*/namespace(*)
这将返回一个 XdmValue，其中包含最外层元素上的命名空间节点列表.然后你就可以了
and this will return a XdmValue containing the list of namespace nodes on the outermost element. You can then just do
for (XdmItem item : result) {
XdmNode ns = (XdmNode)item;
String prefix = ns.getNodeName()==null ? "" : ns.getNodeName().getLocalName();
String uri = ns.getStringValue();
...
}
如果你愿意，你可以通过在文档节点上使用 XdmNode.axisIterator(Axis.CHILD) 来找到最外面的元素来达到同样的效果，然后 XdmNode.axisIterator(Axis.NAMESPACE)) 来查找命名空间节点.
If you prefer you can achieve the same effect by using XdmNode.axisIterator(Axis.CHILD) on the document node to find the outermost element, then XdmNode.axisIterator(Axis.NAMESPACE) to find the namespace nodes.
这篇关于如何使用 XdmNode 从标签中读取命名空间?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
