Python urllib2 URLError 异常? [英] Python urllib2 URLError exception?

问题描述

我之前在 Windows XP 机器上安装了 Python 2.6.2 并运行以下代码:

I installed Python 2.6.2 earlier on a Windows XP machine and run the following code:

import urllib2
import urllib

page = urllib2.Request('http://www.python.org/fish.html')
urllib2.urlopen( page )

我收到以下错误.

Traceback (most recent call last):<br>
  File "C:\Python26\test3.py", line 6, in <module><br>
    urllib2.urlopen( page )<br>
  File "C:\Python26\lib\urllib2.py", line 124, in urlopen<br>
    return _opener.open(url, data, timeout)<br>
  File "C:\Python26\lib\urllib2.py", line 383, in open<br>
    response = self._open(req, data)<br>
  File "C:\Python26\lib\urllib2.py", line 401, in _open<br>
    '_open', req)<br>
  File "C:\Python26\lib\urllib2.py", line 361, in _call_chain<br>
    result = func(*args)<br>
  File "C:\Python26\lib\urllib2.py", line 1130, in http_open<br>
    return self.do_open(httplib.HTTPConnection, req)<br>
  File "C:\Python26\lib\urllib2.py", line 1105, in do_open<br>
    raise URLError(err)<br>
URLError: <urlopen error [Errno 11001] getaddrinfo failed><br><br><br>

推荐答案

import urllib2
response = urllib2.urlopen('http://www.python.org/fish.html')
html = response.read()

你做错了.

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