如何正确地将佛教日期转换为公历日期 iOS [英] How to convert buddhist Date To Gregorian Date Properly iOS

问题描述

如何将 2557 年 1 月 27 日 的佛教日期转换为 2013 年 1 月 27 日.

How to convert Jan 27, 2557 a Buddhist date into Jan 27, 2013.

是的，我知道如果我从 2557 中减去 543，我会得到 2014.但是，我希望它使用 NSDateFormatter 来解决.

Yes, I'm aware that If I subtract 543 from 2557 I'll get 2014. However, I want it to solve using NSDateFormatter.

这是我的代码:

dateFormatter = [[NSDateFormatter alloc] init];
dateFormatter.calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];

 TimeZone *timeZone = [NSTimeZone timeZoneWithName:@"UTC"];
[dateFormatter setTimeZone:timeZone];
[dateFormatter setDateFormat:@"yyyy-MM-dd'T'HH:mm:ss.SSSSS'Z'"];

// Buddhist date should be converted to Gregorian date. But the
// Date still in Buddhist form
NSDate *gregDate = [dateFormatter dateFromString:buddhistDate];

谢谢.

推荐答案

这几乎是从 Apple 文档中复制/粘贴的，只是稍作改动以使用正确的日历类型.我将日期硬编码为您在示例中使用的值.

This is pretty much copy/paste from the Apple docs, with a minor change to use the correct calendar types. I'm hardcoding the date to the values you used in your example.

NSDateComponents *comps = [[NSDateComponents alloc] init];
[comps setDay:27];
[comps setMonth:1];
[comps setYear:2557];

NSCalendar *buddhist = [[NSCalendar alloc]
                         initWithCalendarIdentifier:NSBuddhistCalendar];
NSDate *date = [buddhist dateFromComponents:comps];

NSCalendar *gregorian = [[NSCalendar alloc]
                      initWithCalendarIdentifier:NSGregorianCalendar];
NSUInteger unitFlags = NSDayCalendarUnit | NSMonthCalendarUnit |
NSYearCalendarUnit;
NSDateComponents *components = [gregorian components:unitFlags fromDate:date];

NSInteger day = [components day]; 
NSInteger month = [components month];
NSInteger year = [components year];

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