属性必须是可读写的,而其主要属性必须是只读的 [英] Attribute must be readwrite while its primary must be read only

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本文介绍了属性必须是可读写的,而其主要属性必须是只读的的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在情节提要中添加了一个 UITextView,在这种情况下,我为它创建了一个属性并将其连接到 UIView 的子视图(称为 FieldView)中.楼盘是这样的

I added a UITextView to storyboard that I created a property for and connected in a subview of UIView (called FieldView) in this case. The property was like this

@property (strong, nonatomic) UITextView * instructions;

那个 FieldView 是 viewController 的一个属性

That FieldView is a property of the viewController

@property (strong, nonatomic) IBOutlet FieldView *fieldView;

当我想在 viewController 中使用代码隐藏 UITextView *指令时,我在 .h 文件中声明了该属性,以便我最终可以在按下按钮时执行此操作

When I wanted to hide the UITextView *instructions with code in the viewController, I declared the property in the .h file so that I could eventually do this when a button was pressed

 self.fieldView.instructions.hidden = YES;

但是,xCode 给了我一个错误

However, xCode's giving me an error

 illegal redeclaration of property in class extension FieldView, attribute must be readwrite while its primary must be readonly

当我在 .h 和 .m 文件中添加 readwrite 时

When I added readwrite in both the .h and .m files

@property (weak, nonatomic, readwrite) IBOutlet UITextView *instructions;

it said `perhaps you intended this to be a readwrite redeclaration of a readonly public property

做我想做的事情的正确方法是什么?

What is the correct way to do what I am trying to do?

推荐答案

要解决您的问题,您需要在 .h 文件和 readwrite<中声明 readonly 属性.m 文件中的/code> 属性:

To resolve your issue you need declare readonly property in .h file and readwrite property in .m file:

//FieldView.h
@interface FieldView
@property (nonatomic, readonly, strong) UITextView *instructions;
@end

// FieldView.m
@interface FieldView()
@property (nonatomic, readwrite, strong) IBOutlet UITextView *instructions;
@end

这篇关于属性必须是可读写的,而其主要属性必须是只读的的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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