有第二个 okHTTP 请求等待第一个完成 Android [英] Have second okHTTP request wait for the first to finish Android
问题描述
我试图调用 IMDb API 2 次,第一次调用并获取该电影/节目的 ID,第二次它使用该 ID 获取有关该电影/节目的所有信息,我还需要应用程序另一部分的 ID,这就是我这样做的原因.问题是第二个调用不是等待第一个调用完成.我认为这就是为什么当我尝试使用变量时变量没有更新的原因.这是我的 onCreate 方法,所有这一切都发生了,出于显而易见的原因,我取出了一些 API 密钥:
I am trying to call and IMDb API 2 times, the first time it calls and gets the ID for that movie/show and the second time it uses that ID to get all the information about that movie/show, I also need that ID for another part of the app so that is why I am doing it this way. The problem is that the second call isn't waiting for the first call to be done. I think this is why the variables aren't updated when I am trying to use them. This is my onCreate method where all this is happening, I took out some of the API key for obvious reasons:
@Override
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.imdb_activity);
mTextViewResult = findViewById(R.id.text_view_result);
OkHttpClient client1 = new OkHttpClient();
//change the url to be generic and usable for user input
String urlforID = "https://movie-database-imdb-alternative.p.rapidapi.com/?page=1&r=json&s=Avengers";
final Request request = new Request.Builder()
.url(urlforID)
.get()
.addHeader("x-rapidapi-host", "movie-database-imdb-alternative.p.rapidapi.com")
.addHeader("x-rapidapi-key", "KEYGOESHERE")
.build();
client1.newCall(request).enqueue(new Callback()
{
@Override
public void onFailure(Call call, IOException e)
{
e.printStackTrace();
}
@Override
public void onResponse(Call call, Response response) throws IOException
{
if(response.isSuccessful())
{
String myResponse = response.body().string();
try
{
myObj = new JSONObject(myResponse);
}
catch (JSONException e)
{
e.printStackTrace();
}
try
{
myArray = myObj.getJSONArray("Search");
// responseID = new String[myArray.length()];//might have to subtract 1
for(int i = 0; i < myArray.length(); i++)
{
JSONObject obj1 = myArray.getJSONObject(i);
responseID[i] = obj1.getString("imdbID");
// Log.d("id","the id that was just put in was: " + responseID[i]);
}
}
catch(JSONException e)
{
e.printStackTrace();
}
imdb_activity.this.runOnUiThread(new Runnable()
{
@Override
public void run()
{
//new ReadJsonForID().execute();
Log.d("id", "The id is: " + responseID[0]);
mTextViewResult.setText(responseID[0]);
}
});
}
}
});
//this is where call 2 would happen but it is not saving the variable how it should
Log.d("id", "The id is after finish: " + mTextViewResult.getText());
推荐答案
您可以使用 java.util.concurrent
包中的 CountDownLatch
-class.在第一次调用中,countDownLatch
被实例化,在第二次调用中,您等待 CountDownLatch
.这可能需要将第二个任务放在 AsyncTask
中.
You could use CountDownLatch
-class in package java.util.concurrent
. In the first call, the countDownLatch
is instantiated and in the second call, you await the CountDownLatch
. This maybe require to put the second task in an AsyncTask
.
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