删除和ArrayList的替换重复 [英] Remove and Replace Duplicates in ArrayList

问题描述

我如何消除对ArrayList的重复号码，并更换新？

我想没有他们复制打印的数字。

这是我的code：

 进口的java.util.ArrayList;
进口java.util.HashSet中;
进口java.util.Set中;
进口javax.swing.JOptionPane中;公共类的测试{
    公共静态无效的主要（字串[] args）{
        ArrayList的＆LT;整数GT;人=新的ArrayList＆LT;整数GT;（）;        INT选择=的Integer.parseInt（JOptionPane.showInputDialog（多少号？）;
        的for（int i = 0; I＆LT; OPC;我++）{
            al.add（的Integer.parseInt（JOptionPane.showInputDialog（哪个数字？）））;
        }        SET＆LT;整数GT; S =新的HashSet＆LT;＆GT;（）;
        对于（整数D：人）{
            如果（s.add（四）== FALSE）
                JOptionPane.showMessageDialog（NULL，数字+ D + + al.lastIndexOf（D位置被复制））;
                JOptionPane.showMessageDialog（NULL，更换新号码）; //这是我想如果可能的话来代替数字
            }
        JOptionPane.showMessageDialog（你的号码没有重复：）; //这是它将打印
        }
    }
}
 

解决方案

prevent进入重复号码，当用户输入他们，而不是检查和后来替换它们。搜索结果做，在这个地方

 的for（int i = 0; I＆LT; OPC;我++）{
    al.add（的Integer.parseInt（JOptionPane.showInputDialog（哪个数字？）））;
}
 

Chceck如果一个数字已经存在，如果是，则要求另一个不重复，如果是，则添加它，并要求下一个数字：

 的for（int i = 0; I＆LT; OPC;我++）{
    INT为mynumber =的Integer.parseInt（JOptionPane.showInputDialog（哪个数字？））;
    而（真）{
        如果（！al.contains（mynumber的））
           al.add（mynumber的）;
           打破;
        }
        为mynumber =的Integer.parseInt（JOptionPane.showInputDialog（这个数字是一个重复，再输入另一号码））;
    }
}
 

结果
========编辑================== 搜索结果
我已经纠正了这个例子。还有就是缺少 {在如果在上面的（previous）之一：

 公共类MmuClass {    公共静态无效的主要（字符串... wwwx）{
        清单＆LT;整数GT; LST = Arrays.asList（4,2，6，-6，9）;        ArrayList的＆LT;整数GT;人=新的ArrayList＆LT;整数GT;（）;        的for（int i = 0;我小于5;我++）{
            INT为mynumber =的Integer.parseInt（JOptionPane.showInputDialog（哪个数字？））;
            而（真）{
                如果（！al.contains（mynumber的））{
                    al.add（mynumber的）;
                    打破;
                }
                为mynumber =的Integer.parseInt（
                        JOptionPane.showInputDialog（这个数字是一个重复，再输入另一号码））;
            }
            。al.stream（）的forEach（的System.out ::的println）;
        }
    }
}
 

How do I remove duplicate numbers on ArrayList and replace them with new ones?

I want to print the numbers without them duplicating.

This is my code:

import java.util.ArrayList;
import java.util.HashSet;
import java.util.Set;
import javax.swing.JOptionPane;

public class Test {
    public static void main(String[] args) {
        ArrayList<Integer> al = new ArrayList<Integer>();

        int opt = Integer.parseInt(JOptionPane.showInputDialog("How many numbers?");
        for (int i=0 ; i < opc ; i++) {
            al.add(Integer.parseInt(JOptionPane.showInputDialog("Which numbers?")));
        }

        Set<Integer> s = new HashSet<>();
        for (Integer d : al){
            if (s.add(d) == false)
                JOptionPane.showMessageDialog(null,"The number " + d + " was duplicated in position " + al.lastIndexOf(d));
                JOptionPane.showMessageDialog(null,"Replace new number"); //This is where I would like to replace the numbers if possible
            }
        JOptionPane.showMessageDialog("Your numbers without duplicates: "); //This is where it would print
        }
    }
}

解决方案

Prevent from entering duplicate numbers when the user enters them, instead of checking and replacing them later.

Do it in this place:

for (int i=0 ; i < opc ; i++) {
    al.add(Integer.parseInt(JOptionPane.showInputDialog("Which numbers?")));
}

Chceck if a number already exists, if yes then ask for another not duplicated, if yes then add it and ask for next number :

for (int i=0 ; i < opc ; i++) {
    int myNumber = Integer.parseInt(JOptionPane.showInputDialog("Which numbers?"));
    while( true ){
        if( ! al.contains( myNumber ))
           al.add( myNumber );
           break;
        }
        myNumber = Integer.parseInt(JOptionPane.showInputDialog("This number is a duplicate, enter another number again"));
    }
}

======== EDIT ==================

I've corrected the example. There is missing { after if in the above (previous) one:

public class MmuClass {

    public static void main(String... wwwx) {
        List<Integer> lst = Arrays.asList(4, 2, 6, -6, 9);

        ArrayList<Integer> al = new ArrayList<Integer>();

        for (int i = 0; i < 5; i++) {
            int myNumber = Integer.parseInt(JOptionPane.showInputDialog("Which numbers?"));
            while (true) {
                if (!al.contains(myNumber)) {
                    al.add(myNumber);
                    break;
                }
                myNumber = Integer.parseInt(
                        JOptionPane.showInputDialog("This number is a duplicate, enter another number again"));
            }
            al.stream().forEach(System.out::println);
        }
    }
}

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