用select子句在oracle中编写一个返回id的插入语句 [英] Write an insert statement with select clause returning id in oracle

问题描述

我正在尝试按如下方式编写查询:

I am trying to write a query as follows:

例如:

 DECLARE 
 V_Output varchar(20):='';

 BEGIN
   INSERT INTO T(ID, MY_PK, NAME, VALUE)
   (SELECT ID, NEXT_TRAN_VALUE('T'), NAME, VALUE FROM T WHERE MY_PK = 'NO0000000000013');
   RETURNING MY_PK INTO V_Output;
   DBMS_OUTPUT.PUT(V_Output);
 END;

使用下面的函数

create or replace FUNCTION NEXT_TRAN_VALUE (field IN VARCHAR2)   RETURN 
VARCHAR2
IS
n_value   VARCHAR2 (20);
P_APR     VARCHAR2(3);

CURSOR rec_exists IS SELECT * FROM TRANSACTION_SEQ where SEQ_NAME = field ;      
jk_seq_rec  TRANSACTION_SEQ%ROWTYPE;   
PRAGMA AUTONOMOUS_TRANSACTION;
BEGIN
SELECT LC_CODE into P_APR FROM LOCATION_CONFIG;
OPEN rec_exists;
FETCH rec_exists INTO jk_seq_rec;

IF rec_exists%FOUND THEN
    UPDATE TRANSACTION_SEQ SET curr_value =   curr_value + 1 WHERE SEQ_NAME = field;
    COMMIT;
END IF;

--SELECT curr_value INTO n_value FROM TRANSACTION_SEQ WHERE SEQ_NAME = field; 
END;

但是，它显示错误.

select 语句总是返回要插入的单个语句，所以在我看来它应该返回插入行的 my_pk.

the select statement shall always return single statement to be inserted, so in my opinion it should return the my_pk of inserted row.

推荐答案

我使用 Cursor 来解决问题.

I use Cursor to resolve the issue.

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