如何将成员函数指针传递给模板函数中的重载方法? [英] How to pass a member function pointer to an overloaded method in a template function?

问题描述

我提到了这个有些类似的问题.但是这里的情况有所不同:

I referred to this somewhat similar question. However here the scenario is different:

struct A
{
  void foo (int i) {} // choice
  void foo (double i) {}
};

template<typename ObjType, typename FuncPtr>
void ReceiveFuncPtr (ObjType o, FuncPtr pf)
{
 (o.*pf)(1);
}

int main ()
{
  A obj;
  ReceiveFuncPtr(obj, &A::foo); // don't want typecast here
}

在上面的测试代码中，我在A中有一个重载的foo.如果只有 1 个 foo 那么代码工作正常.但是对于重载的情况，编译器会抱怨:

In the above test code, I have an overloaded foo inside A. Had there been only 1 foo then the code works fine. But for overloading case, compiler complains as:

错误:没有匹配的调用函数到 `ReceiveFuncPtr(A&, [未解析重载函数类型])'

error: no matching function for call to `ReceiveFuncPtr(A&, [unresolved overloaded function type])'

不是在调用 ReceiveFuncPtr() 时显式类型转换，我们有什么方法可以对其 template 参数进行一些更改并使其能够接收 foo(int) 版本总是用于任何类似的 class A ?

Instead of explicit typecasting while calling ReceiveFuncPtr(), is there any way that we can make some changes in its template parameter and enable it to receive foo(int) version always for any similar class A ?

编辑:想法是在调用函数时不要担心类型.它应该很简单，ReceiveFuncPtr(obj, &A::foo); 让 template 完成它的工作.

Edit: Idea is not to worry about the type while calling the function. It should be as simple as, ReceiveFuncPtr(obj, &A::foo); And let the template do its work.

推荐答案

这个怎么样:

template<typename ObjType>
void ReceiveFuncPtr (ObjType o, void (ObjType::*pf)(int))
{
 (o.*pf)(1);
}

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