如何定义一个类 Road 等价于一组具有相同 hasRoadNumber 数据属性值的对象 [英] How to define a class Road to be equivalent to a set of objects with the same value of hasRoadNumber data property

问题描述

我定义了类 RoadSegment 和数据类型属性 hasRoadNumber.所以，现在我想定义 Road 类并声明 Road 是一组具有相同道路编号的 RoadSegments.怎么做?

I defined class RoadSegment and datatype property hasRoadNumber. So, now I want to define class Road and state that a Road is a set of RoadSegments with the same road number. How it can be done?

推荐答案

让我们假设这个数据

<r123> a :Road; :number "123".
<r123.1> a :RoadSegment; :number "123"; :seq 1.
<r123.2> a :RoadSegment; :number "123"; :seq 2.

您可以使用此 GraphDB 规则 (.pie) 轻松推断出您想要的内容:

You can easily infer what you want with this GraphDB rule (.pie):

id: roadSegments
  r <rdf:type> <Road>
  rs <rdf:type> <RoadSegment>
  r <number> n
  rs <number> n
  -------------
  r <hasSegment> rs

好处是规则是动态的，即当您添加/删除/编辑段时，:hasSegment 将动态更新.

The benefit is that the rule is dynamic, i.e. as you add/remove/edit segments, :hasSegment will be updated dynamically.

至于序列，有多种模式可以表示它们.

As for sequences, there are various patterns to represent them.

• rdf:List 是标准的，但非常笨拙.
• 使用序列号使事情变得更容易，例如 https://schema.org/ItemList 使用它(但与上面不同的是，允许一个项目成为多个列表的成员，使用辅助类 https://schema.org/ListItem.

• rdf:List is standard but quite unwieldy.
• Using a sequence number makes things easier, eg https://schema.org/ItemList uses it (but unlike above, allows an item to be member of several lists, using auxiliary class https://schema.org/ListItem.

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