从 Pandas DataFrame 返回单个单元格值 [英] Return single cell value from Pandas DataFrame

问题描述

我想问一个问题，这是这个线程的扩展:

I would like to ask an question that is an extension on this thread:

根据 Pandas 中列中的值从 DataFrame 中选择行.

该线程的代码如下:

import pandas as pd
import numpy as np
df = pd.DataFrame({'A': 'foo bar foo bar foo bar foo foo'.split(),
               'B': 'one one two three two two one three'.split(),
               'C': np.arange(8), 'D': np.arange(8) * 2})
print(df)
#      A      B  C   D
# 0  foo    one  0   0
# 1  bar    one  1   2
# 2  foo    two  2   4
# 3  bar  three  3   6
# 4  foo    two  4   8
# 5  bar    two  5  10
# 6  foo    one  6  12
# 7  foo  three  7  14

print(df.loc[df['D'] == 14])

这将产生以下结果:

   A    B      C   D
7  foo  three  7  14

根据上面的代码，我怎样才能返回单个值"而不是一行.也就是说，我如何返回值 '7' 或值 'foo' 而不是整行?

Based on the code above, how can I return a single 'value' not a row. That is, how can I return the value '7' or value 'foo' as opposed to the entire row?

推荐答案

@JonahWilliams 很接近，这是一个可行的方案:

@JonahWilliams was close, here's a working one:

import pandas as pd
import numpy as np
df = pd.DataFrame({'A': 'foo bar foo bar foo bar foo foo'.split(),
               'B': 'one one two three two two one three'.split(),
               'C': np.arange(8), 'D': np.arange(8) * 2})

print(df.loc[df['D'] == 14]['A'].index.values)

>>>[7]

print(df.loc[df['D'] == 14]['A'].values)

>>>['foo']

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