阵列扩展通过值删除对象 [英] Array extension to remove object by value
问题描述
extension Array {
func removeObject<T where T : Equatable>(object: T) {
var index = find(self, object)
self.removeAtIndex(index)
}
}
不过,我得到关于 VAR指数=发现(个体经营,对象)
'T'是无法转换为'T'
'T' is not convertible to 'T'
我也试过用这种方法签名: FUNC的removeObject(对象:AnyObject)
,不过,我得到了同样的错误:
I also tried with this method signature: func removeObject(object: AnyObject)
, however, I get the same error:
AnyObject'是无法转换为'T'
'AnyObject' is not convertible to 'T'
什么是做到这一点的正确方法?
What is the proper way to do this?
推荐答案
由于 2斯威夫特,这可以用实现的协议扩展方法的。的removeObject()
被定义为符合所有类型的方法
到 RangeReplaceableCollectionType
(特别是关于阵列
),如果
集合的元素是 Equatable
:
As of Swift 2, this can be achieved with a protocol extension method.
removeObject()
is defined as a method on all types conforming
to RangeReplaceableCollectionType
(in particular on Array
) if
the elements of the collection are Equatable
:
extension RangeReplaceableCollectionType where Generator.Element : Equatable {
// Remove first collection element that is equal to the given `object`:
mutating func removeObject(object : Generator.Element) {
if let index = self.indexOf(object) {
self.removeAtIndex(index)
}
}
}
例如:
var ar = [1, 2, 3, 2]
ar.removeObject(2)
print(ar) // [1, 3, 2]
更新雨燕2 / X code 7测试版2:空速速度注意到
评价,现在实际上是可能写在一个通用的类型是模板上更严格的方法,因此该方法
可现在居然被定义为阵列的扩展
:
extension Array where Element : Equatable {
// ... same method as above ...
}
的协议扩展仍具有作为适用于该优点
较大的一组类型。
The protocol extension still has the advantage of being applicable to a larger set of types.
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