未处理的异常:com.parse.parseException android studio [英] Unhandled exception: com.parse.parseException android studio

问题描述

这是我的代码:

 package com.alibdeir.database;

    import android.content.Context;
    import android.support.v7.app.AppCompatActivity;
    import android.os.Bundle;
    import android.view.Menu;
    import android.view.MenuItem;
    import android.view.View;
    import android.widget.Button;
    import android.widget.TextView;
    import android.widget.Toast;

    import com.parse.GetCallback;
    import com.parse.Parse;
    import com.parse.ParseObject;
    import com.parse.ParseQuery;
    import com.parse.SaveCallback;
    import com.parse.ParseException;

    public class MainActivity extends AppCompatActivity {
        TextView output;
        Button increase;
        int currentInt;



        @Override
        protected void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.activity_main);
            Parse.initialize(this, "QeaC0wiXsL9MyRbLaQ***********", "kDjoZVRu4OyWOGxPtPjh**************");
            output =  (TextView) findViewById(R.id.output);
            increase = (Button) findViewById(R.id.increase);
            ParseQuery query = new ParseQuery("int");
            ParseObject o = query.get-("n6zA3CHxGx");
        }
        public void increase(View v) {

            currentInt = Integer.parseInt(output.getText().toString());
            output.setText(currentInt + 1 + "");
        }
    }

注意:ParseQuery 查询 = new ParseQuery("int");ParseObject o = query.get("n6zA3CHxGx");

Notice: ParseQuery query = new ParseQuery("int"); ParseObject o = query.get("n6zA3CHxGx");

悬停在 query.get("n6zA3CHxGx");我有标题中提到的错误.我正在尝试更新解析云中的对象.对象是在云中.请帮忙

On hover of query.get("n6zA3CHxGx"); i have the error mentioned in the title. I am trying to update an object that's in the parse cloud. The object IS in the cloud. Please help

推荐答案

1. 像这样使用 try { .. } catch 尝试处理异常的代码.

1. Trying your code with handle exception using try { .. } catch like this.

try {
Parse.initialize(this, "QeaC0wiXsL9MyRbLaQ***********", "kDjoZVRu4OyWOGxPtPjh**************");
    output =  (TextView) findViewById(R.id.output);
    increase = (Button) findViewById(R.id.increase);
    ParseQuery query = new ParseQuery("int");
    ParseObject o = query.get-("n6zA3CHxGx");
} catch (com.parse.ParseException e1) {
e1.printStackTrace();
}

根据 this 解析论坛讨论ACL 设置默认是公共读取，所有者写入.您可以更改这些以允许其他用户写入.

通过使用以下代码:-

ParseACL postACL = new ParseACL(ParseUser.getCurrentUser());
postACL.setPublicReadAccess(true);
postACL.setPublicWriteAccess(true);

这篇关于未处理的异常:com.parse.parseException android studio的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！