如何从一个字符串中提取号码，并得到int数组？ [英] How to extract numbers from a string and get an array of ints?

问题描述

我有一个字符串变量（基本上是一个英语句子用数字的数目不详），我想所有的数字提取到一个整数数组。我不知道是否有定期的前pressions一个快速的解决方案？

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我用肖恩的解决方案，并改变了它稍微：

 的LinkedList＆LT;串GT;数=新的LinkedList＆LT;串GT;（）;模式P = Pattern.compile（\\\\ D +）;
匹配器M = p.matcher（线）;
而（m.find（））{
   numbers.add（m.group（））;
}
 

解决方案

 模式P = Pattern.compile（ -  \\\\ D +？）;
匹配M = p.matcher（还有比-2和小于12号的详细点击这里）;
而（m.find（））{
  的System.out.println（m.group（））;
}
 

...打印-2和12。

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- ？相匹配的领先的负号 - 可选。 \\ d匹配一个数字，我们需要在Java字符串写入\\作为\\虽然。因此，\\ D + 1相匹配更多个数字

I have a String variable (basically an English sentence with an unspecified number of numbers) and I'd like to extract all the numbers into an array of integers. I was wondering whether there was a quick solution with regular expressions?

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I used Sean's solution and changed it slightly:

LinkedList<String> numbers = new LinkedList<String>();

Pattern p = Pattern.compile("\\d+");
Matcher m = p.matcher(line); 
while (m.find()) {
   numbers.add(m.group());
}

解决方案

Pattern p = Pattern.compile("-?\\d+");
Matcher m = p.matcher("There are more than -2 and less than 12 numbers here");
while (m.find()) {
  System.out.println(m.group());
}

... prints -2 and 12.

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-? matches a leading negative sign -- optionally. \d matches a digit, and we need to write \ as \ in a Java String though. So, \d+ matches 1 more more digits

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