xpath - 使用包含通配符 [英] xpath - using contains with a wildcard

问题描述

我有以下几点，并试图看看是否有更好的方法.我知道它可以使用开始/包含来完成.我正在使用 firefox 10 进行测试，我相信它实现了 xpath 2.+.

I have the following, and trying to see if there's a better approach. I know it cn be done using starts-with/contains. I'm testing with firefox 10, which I believe implements xpath 2.+.

测试节点是

<a id="foo">
.
.
.
<a id="foo1">
.
<a id="foo2">

有没有办法使用通配符来获取 foo1/foo2 节点..

Is there a way to use wildcards to be able to get the foo1/foo2 nodes..

类似的东西

//a[@id =* 'foo'] 

or 

//a[contains(@id*,'foo')] 

这会说，给我一个a"，其中 id 以foo"开头，但有额外的字符......然后这将跳过带有foo"的第一个节点

Which would say, give me the "a" where the id starts with "foo" but has additional chars... This would then skip the 1st node with the "foo"

我以为我看过一篇关于此的文章，但找不到！

I thought I had seen an rticle on this, but can't find it!

我记得，那篇文章说 xpath 有一组运算符，可用于指定字符串中给定模式的开始/结束.

As I recall, the article stated that xpath had a set of operators that could be used to designate the start/end of a given pattern in a string.

谢谢

推荐答案

使用:

//a[@id[starts-with(., 'foo') and string-length() > 3]]

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