正则表达式替换重复的字符串模式 [英] Regex to replace a repeating string pattern

问题描述

我需要用每个基本构造单元替换单词中的重复模式.例如我有字符串TATATATA"，我想用TA"替换它.此外，我可能会替换 2 次以上的重复，以避免替换正常单词.

I need to replace a repeated pattern within a word with each basic construct unit. For example I have the string "TATATATA" and I want to replace it with "TA". Also I would probably replace more than 2 repetitions to avoid replacing normal words.

我正在尝试使用 replaceAll 方法在 Java 中执行此操作.

I am trying to do it in Java with replaceAll method.

推荐答案

我想你想要这个(适用于任何长度的重复字符串):

I think you want this (works for any length of the repeated string):

String result = source.replaceAll("(.+)\\1+", "$1")

或者，优先考虑较短的匹配:

Or alternatively, to prioritize shorter matches:

String result = source.replaceAll("(.+?)\\1+", "$1")

它首先匹配一组字母，然后再次匹配(在匹配模式本身中使用反向引用).我试过了，它似乎奏效了.

It matches first a group of letters, and then it again (using back-reference within the match pattern itself). I tried it and it seems to do the trick.

示例

String source = "HEY HEY duuuuuuude what'''s up? Trololololo yeye .0.0.0";

System.out.println(source.replaceAll("(.+?)\\1+", "$1"));

// HEY dude what's up? Trolo ye .0

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