用正则表达式检测非空字符串? [英] Detect non-empty string with regexp?

问题描述

如何编写检测字符串非空的 PHP 正则表达式?

How do I write a PHP regexp which detects that a string is not empty?

空意味着，在这种情况下是 0 个字符.例如，单个空格或单个换行符算作非空.

Empty means, in this case 0 characters. A single space, or a single newline counts as not empty, for instance.

(它必须是适合 preg_match() 的正则表达式，因为我有一个包含各种正则表达式的查找表，并且不想以任何特殊的方式处理这种情况，如果在这里不使用正则表达式会使代码复杂化.)

(It has to be regexp suitable for preg_match(), since I have a lookup table with various regexps and don't want to handle this case in any special way, it would complicate the code to not use a regexp here.)

更新:

出于可悲的原因，我也不能在 // 之外使用任何正则表达式修饰符，例如s".

I also can not use any regex modifiers such as "s" outside the // for sad reasons.

^{致反对者:问题是不是太简单了?还是不够清楚?}

推荐答案

/[\s\S]/

匹配任何字符，即使您不能使用 /s 修饰符.

matches any character, even if you can't use the /s modifier.

您不需要量词(+)，因为如果一个字符匹配，则条件已经满足.

You don't need a quantifier (+) because if one character matches, then the condition is already fulfilled.

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