将 Javascript 正则表达式转换为 PHP (PCRE) 表达式 [英] Convert Javascript Regular Expression to PHP (PCRE) Expression

问题描述

我对正则表达式很感兴趣，我有这个在 javascript(和 flash)中工作的正则表达式，但我无法在 PHP 中工作

I am up to my neck in regular expressions, and I have this regular expression that works in javascript (and flash) that I just can't get working in PHP

这是:

  var number
      = '(?:-?\\b(?:0|[1-9][0-9]*)(?:\\.[0-9]+)?(?:[eE][+-]?[0-9]+)?\\b)';
  var oneChar = '(?:[^\\0-\\x08\\x0a-\\x1f\"\\\\]'
      + '|\\\\(?:[\"/\\\\bfnrt]|u[0-9A-Fa-f]{4}))';
  var str = '(?:\"' + oneChar + '*\")';
  var varName = '\\$(?:' + oneChar + '[^ ,]*)';
  var func = '(?:{[ ]*' + oneChar + '[^ ]*)';
  // Will match a value in a well-formed JSON file.
  // If the input is not well-formed, may match strangely, but not in an unsafe
  // way.
  // Since this only matches value tokens, it does not match whitespace, colons,
  // or commas.
  var jsonToken = new RegExp(
      '(?:false|true|null'
      +'|[\\}]'
      + '|' + varName
      + '|' + func
      + '|' + number
      + '|' + str
      + ')', 'g');

如果你想在这里完全组装它:

If you want it fully assembled here it is:

/(?:false|true|null|[\}]|\$(?:(?:[^\0-\x08\x0a-\x1f"\\]|\\(?:["/\\bfnrt]|u[0-9A-Fa-f]{4}))[^ ,]*)|(?:{[ ]*(?:[^\0-\x08\x0a-\x1f"\\]|\\(?:["/\\bfnrt]|u[0-9A-Fa-f]{4}))[^ ]*)|(?:-?\b(?:0|[1-9][0-9]*)(?:\.[0-9]+)?(?:[eE][+-]?[0-9]+)?\b)|(?:"(?:[^\0-\x08\x0a-\x1f"\\]|\\(?:["/\\bfnrt]|u[0-9A-Fa-f]{4}))*"))/g

有趣的是，它与 JSON 非常相似.

Interestingly enough, its very similar to JSON.

我需要这个正则表达式才能在 PHP 中工作...

I need this regular expression to work in PHP...

这是我在 PHP 中的内容:

Here's what I have in PHP:

    $number = '(?:-?\\b(?:0|[1-9][0-9]*)(?:\\.[0-9]+)?(?:[eE][+-]?[0-9]+)?\\b)';
    $oneChar = '(?:[^\\0-\\x08\\x0a-\\x1f\"\\\\]|\\\\(?:[\"/\\\\bfnrt]|u[0-9A-Fa-f]{4}))';
    $string = '(?:\"'.$oneChar.'*\")';
    $varName = '\\$(?:'.$oneChar.'[^ ,]*)';
    $func = '(?:{[ ]*'.$oneChar.'[^ ]*)';

    $jsonToken = '(?:false|true|null'
      .'|[\\}]'
      .'|'.$varName
      .'|'.$func
      .'|'.$number
      .'|'.$string
      .')';

    echo $jsonToken;

    preg_match_all($jsonToken, $content, $out);

    return $out;

如果我尝试使用 preg_match_all() 会发生以下情况:

Here's what happens if I try using preg_match_all():

警告:preg_match_all()[function.preg-match-all]:编译失败:在偏移量 0 处无需重复在线 88

Warning: preg_match_all() [function.preg-match-all]: Compilation failed: nothing to repeat at offset 0 on line 88

任何帮助将不胜感激！

谢谢，马特

推荐答案

我猜这是因为您没有分隔符之间的正则表达式.

试试:

$jsonToken = '@(?:false|true|null'
      .'|[\\}]'
      .'|'.$varName
      .'|'.$func
      .'|'.$number
      .'|'.$string
      .')@';

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