R:绘图时 x 轴上的字符而不是级别 #? [英] R: Character instead of level # on x axis when plotting?

问题描述

我需要帮助在 x 轴上绘制月份名称，而不是指定月份的级别.我正在处理一个水年"，所以 10 月被指定为 1 级，9 月结束时为 12 级.我相信这很容易，只是我不经常使用因子.谢谢！

I need help plotting month names on the x axis, instead of the level the months are assigned. I am working with a "water year", so October is assigned to be level 1, and ending with September being level 12. I'm sure this is easy, I just don't often work with factors. Thanks!

研究完成:根据 R 中的数字向量绘制字符向量

R 绘图，x 轴上的日期

这是我的数据的简化示例

Here is a simplified example of my data

    Months<-c("Jan"=4,"Feb"=5,"Mar"=6,"Apr"=7,"May"=8,"Jun"=9,"Jul"=10,
    "Aug"=11,"Sep"=12,"Oct"=1,"Nov"=2,"Dec"=3)

    Data<-c(1,2,3,4,5,6,7,8,9,10,11,12)

    df<-data.frame(Months,Data)

  >df
      Months Data
  Jan      4    1
  Feb      5    2
  Mar      6    3
  Apr      7    4
  May      8    5
  Jun      9    6
  Jul     10    7
  Aug     11    8
  Sep     12    9
  Oct      1   10
  Nov      2   11
  Dec      3   12

    plot(Data~factor(Months), df,las=2)

这会将具有正确月份的数据放在正确的位置，只是错误的标签.

This puts the data in the correct place with the correct month, just the wrong labels.

推荐答案

我们可以在 plot 中使用 xaxt = "n" 然后使用 axiscode> 更改 xaxis 刻度标签

We can use xaxt = "n" in plot and then with axis change the xaxis tick labels

plot(Data ~ Months, transform(df, Months = match(row.names(df), 
                       month.abb)), las = 2, xaxt = "n", type = "b", col = "blue")
axis(1, at = seq_len(nrow(df)), row.names(df))

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