为日期范围内的每个月生成单独的行 [英] Generating separate rows for each month in a date range

问题描述

基本上我有一行数据，例如:

Basically I have one row of data, for example:

ID -   Start_Date -  End_Date

------------------------------------

XXA   1/23/14        3/12/14

我想为 Start_Date 和 End_Date 之间的每个月创建一行，为每个 ID，例如:

And I want to create one row for each month between the Start_Date and End_Date, for each ID, for example:

ID -  Month -     Year

--------------------------

XXA  January      2014

XXA  February     2014

XXA  March         2014

执行此操作的最佳和最有效方法是什么?我正在考虑使用游标，但是一旦创建了这个表，我就需要将其他的加入到这个表中.我是 oracle 的新手，我不确定在运行游标并创建临时表后是否可以加入其他表.任何帮助将不胜感激.

Which is the best and most efficient way of doing this? I was thinking of using a cursor, but once this table is created, I need to join other ones to this one. I am new to oracle, and I am not sure if you can join other tables after you run a cursor and create a temporary table. Any help would be greatly appreciated.

推荐答案

您可以通过使用 CONNECT BY 语法来使用简单的行生成技术:

You can use a simple row generation technique by using the CONNECT BY syntax:

with sample_data as 
  (select 'XXA' id, to_date('1/23/14','MM/DD/RR') start_date, to_date('3/12/14','MM/DD/RR') end_date from dual)
select id, to_char(add_months(start_date,level - 1),'Month YYYY') date_column
from sample_data
connect by level <= extract(month from end_date) - extract(month from start_date) + 1;

编辑添加 DISTINCT 应该允许它跨行工作，我相信，尽管我有兴趣被证明是错误的.编辑 2 修改示例以处理多年(最初应该这样做).(参见示例 http://sqlfiddle.com/#!4/9eecb/4097/0.)

Edit Adding DISTINCT should allow this to work across rows, I believe, although I would be interested to be proven wrong. Edit 2 Modified example to handle multiple years (should have done that originally). (See example http://sqlfiddle.com/#!4/9eecb/4097/0.)

with sample_data as 
  ( select 'XXA' id, to_date('1/23/14','MM/DD/RR') start_date, to_date('3/12/15','MM/DD/RR') end_date from dual union all    
    select 'XXB' id, to_date('4/12/14','MM/DD/RR') start_date, to_date('6/18/15','MM/DD/RR') end_date from dual )
select distinct 
  id,
  to_char(add_months(start_date,level - 1),'Month YYYY') date_column,
  add_months(start_date,level -1) sortkey
from sample_data
connect by level <= ceil(months_between(trunc(end_date,'MM'), trunc(start_date,'MM'))) + 1
order by id, sortkey;

在我的沙箱数据库中，这会产生:

In my sandbox DB this yields:

ID  DATE_COLUMN     SORT_COL
XXA January   2014  23-JAN-2014 00:00:00
XXA February  2014  23-FEB-2014 00:00:00
XXA March     2014  23-MAR-2014 00:00:00
XXB April     2014  12-APR-2014 00:00:00
XXB May       2014  12-MAY-2014 00:00:00
XXB June      2014  12-JUN-2014 00:00:00

这篇关于为日期范围内的每个月生成单独的行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！