如何使用新的 char16_t 和 u8 类型? [英] How to use the new char16_t and u8 types?

问题描述

c11 使用 utf-8 utf-16 和 utf-32 的内置类型改进了编码支持.

c11 improve encoding support with built-in types for utf-8 utf-16 and utf-32.

但是我完全找不到在标准函数中使用它们的参考.我发现的是如何在 c++11 中而不是在 C 中使用它们.

However I was completely unable to find reference on using them in Standard functions. All I found is how to use them in c++11 not in C.

例如，如何打印一个 char32_t?

So how to printf a char32_t for example?

推荐答案

没什么好说的:C11 只引入了四个新的标准库函数，用于处理 char16_t 和 char32_t，将它们转换为/从多字节字符串:

There isn't much to say: C11 only introduced four new standard library functions for working with char16_t and char32_t, which convert them to/from multibyte strings:

• char16_t:mbrtoc16() 和 c16rtomb()
• char32_t:mbrtoc32() 和 c32rtomb()

对于 printf()，它们的行为类似于 uint_least16_t 和 uint_least32_t 类型，因此您可以对它们使用相同的格式说明符:

With respect to printf(), they behave like uint_least16_t and uint_least32_t types, so you can use the same format specifiers for them:

#include <inttypes.h>

char32_t x = ...;
printf("%" PRIuLEAST32 "\n", x);

如果要将值打印为字符，则需要使用上面的转换函数.

If you want to print the value as a character, you will need to use the conversion functions above.

使用 char16_t 和 char32_t 字符和字符串文字是相同的在 C11 和 C++11 中.

Working with char16_t and char32_t character and string literals is identical in both C11 and C++11.

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