初始化int数组 [英] initializing an array of ints

问题描述

有没有人有一种方法来初始化的 INT 秒的阵列（任何多字节类型是罚款真的），到非零和非-1价值根本？我的意思是，有没有办法做到这一点的一个内胆，无需逐个做的每一个元素：

Does anyone have a way to initialize an array of ints (any multi-byte type is fine really), to a non-zero and non -1 value simply? By which I mean, is there a way to do this in a one liner, without having to do each element individually:

int arr[30] = {1, 1, 1, 1, ...}; // that works, but takes too long to type

int arr[30] = {1}; // nope, that gives 1, 0, 0, 0, ...

int arr[30];
memset(arr, 1, sizeof(arr)); // That doesn't work correctly for arrays with multi-byte
                             //   types such as int

仅供参考，以这种方式对静态数组使用 memset的（）给出：

arr[0] = 0x01010101
arr[1] = 0x01010101
arr[2] = 0x01010101

另一种选择：

for(count = 0; count < 30; count++)
   arr[count] = 1;    // Yup, that does it, but it's two lines.

任何人有其他的想法？只要是C code，对解决方案没有限制。 （其他库都很好）

Anyone have other ideas? As long as it's C code, no limits on the solution. (other libs are fine)

推荐答案

这是一个GCC扩展：

int a[100] = {[0 ... 99] = 1};

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