提取两个双引号之间的所有数据 [英] Extract all data in between two double quotes

问题描述

我正在尝试使用 powershell 正则表达式从 AssemblyInfo.cs 文件中提取版本数据.下面的正则表达式是我最好的尝试，但它只提取字符串 [assembly: AssemblyVersion(". 我已经把这个正则表达式放入几个 web 正则表达式测试器中，它看起来像我想要的那样，然而，这是我第一次使用 powershell 正则表达式，所以我可能看错了.

I'm trying to use a powershell regex to pull version data from the AssemblyInfo.cs file. The regex below is my best attempt, however it only pulls the string [assembly: AssemblyVersion(". I've put this regex into a couple web regex testers and it LOOKS like it's doing what I want, however this is my first crack at using a powershell regex so I could be looking at it wrong.

$s = '[assembly: AssemblyVersion("1.0.0.0")]'
$prog = [regex]::match($s, '([^"]+)"').Groups[1].Value

推荐答案

您还需要包含开始的双引号，否则它会从头开始捕获，直到到达第一个 ".>

You also need to include the starting double quotes otherwise it would start capturing from the start until the first " is reached.

$prog = [regex]::match($s, '"([^"]+)"').Groups[1].Value
                            ^

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