下一个质数 Java 仅适用于某些数字 [英] Next Prime number Java only working with certain numbers
本文介绍了下一个质数 Java 仅适用于某些数字的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
此功能仅适用于某些数字,但对于 15 或 5,它不能给我正确的下一个素数.
This function its only working for certain numbers, but for 15, or 5 it does not give me correct next prime.
public static int nextPrime(int n) {
boolean isPrime = false;
int m = (int) Math.ceil(Math.sqrt(n));
int start = 3;
if (n % 2 == 0) {
n = n + 1;
}
while (!isPrime) {
isPrime = true;
for (int i = start; i <= m; i = i + 2) {
if (n % i == 0) {
isPrime = false;
break;
}
}
if (!isPrime) {
n = n + 2;
}
}
return n;
}
推荐答案
你不需要去到sqrt(n),你需要去到你正在评估的sqrt(number)
You don't need to go upto sqrt(n), you need to go upto sqrt(number) that you are evaluating
例如考虑您通过 n = 5
for example consider you pass n = 5
它将从 3 开始循环,并在 4 结束循环,这不是您找到下一个质数所需的
it will start loop from 3 and it will end the loop at 4 that is not what you need to find next prime number
外循环从 n + 1 开始,直到找到素数内循环你应该从 3 和 sqrt(numberUnderIteration) 开始
outer loop start from n + 1 until you find prime inner loop you should start from 3 and sqrt(numberUnderIteration)
这篇关于下一个质数 Java 仅适用于某些数字的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文