printf 在 C 中给我错误的输出 [英] printf giving me incorrect output in C

问题描述

这可能是一个非常基本的问题，但我在任何地方都找不到答案，这是我在用 C 编程几周后第一次遇到这个问题.本质上，如果我写一些看起来像这样的代码这个:

This is probably a very elementary problem, but I cannot find the answer anywhere, and this is the first time I've had the problem after several weeks of programming in C. In essence, if I write some code looking something like this:

int size;
scanf("%d", &size);
printf("size is %d", &size);

如果我输入，比如说，size = 2，程序会打印出类似 133692 或类似数字的内容.为什么是这样?我在这里做错了什么?

If I input, say, size = 2, the program will print back out something along the lines of 133692 or a similar number. Why is this? What have I done wrong here?

推荐答案

尝试

printf("size is %d", size);

& 为您提供变量的内存位置(地址).

& gives you the memory location (address) of a variable.

printf("size is %d", &size);

所以，上面打印的是size的内存位置(地址)，而不是size中存储的值.

So, the above will print the memory location(address) of size, not the value stored in size.

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