从一个数组在JavaScript中提取最重复的值（用jQuery） [英] Extracting the most duplicate value from an array in JavaScript (with jQuery)

问题描述

我有几个阵列来处理。我需要提取每个阵列最重复的值。

I have several array to deal with. I need to extract the most duplicate value from each array.

从 [3,7，7,7] ，我需要找到值 7 。每个数组的大小为4。现在，我没有去想的时候最重复的值不止一个，如 [3,7，7,7] 。所有的值是一个数。

From [3, 7, 7, 7], I need to find the value 7. Each array size is 4. For now, I don't have to think about when the most duplicate values are more than one such as [3, 7, 7, 7]. All the values are a number.

我看了看各地的网络。我发现了几个办法，使阵列成为的uniq（）。但我还没有找到一种方式来获得重复的值。我使用jQuery，但原料JavaScript是罚款这项任务。

I looked around the web. I found several ways to make an array to become uniq(). But I haven't found a way to get the duplicate value. I am using jQuery, but raw JavaScript is fine for this task.

推荐答案

未在效率方面完美的，但做这项工作：

Not perfect in terms of efficiency, but does the job:

var nums = [3, 7, 7, 7];
var freqs = {};
var max_index;
var max_value = -1/0; // Negative infinity.

$.each(nums, function(i, v) {
  if (freqs[v] != undefined) {
    freqs[v]++;
  } else {
    freqs[v] = 1;
  }
});
$.each(freqs, function(num, freq) {
  if (freq > max_value) {
    max_value = freq;
    max_index = num;
  }
});

if (max_index != undefined) {
  alert("Most common element is " + max_index + " with " + max_value + " repetition(s).");
}
​

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