PHP:准备好的语句，需要 IF 语句帮助 [英] PHP: prepared statement, IF statement help needed

问题描述

我有以下代码:

$sql = "SELECT name, address, city FROM tableA, tableB WHERE tableA.id = tableB.id";

if (isset($price) ) {
    $sql = $sql . ' AND price = :price ';
}
if (isset($sqft) ) {
    $sql = $sql . ' AND sqft >= :sqft ';
}
if (isset($bedrooms) ) {
    $sql = $sql . ' AND bedrooms >= :bedrooms ';
}


$stmt = $dbh->prepare($sql);


if (isset($price) ) {
    $stmt->bindParam(':price', $price);
}
if (isset($sqft) ) {
    $stmt->bindParam(':price', $price);
}
if (isset($bedrooms) ) {
    $stmt->bindParam(':bedrooms', $bedrooms);
}


$stmt->execute();
$result_set = $stmt->fetchAll(PDO::FETCH_ASSOC);

我注意到的是冗余的多个 IF 语句.

What I notice is the redundant multiple IF statements I have.

问题:有没有什么办法可以清理我的代码，这样我就不会在准备好的语句中使用这些多个 IF 语句?

Question: is there any way to clean up my code so that I don't have these multiple IF statements for prepared statements?

推荐答案

这与一个用户的问题很相似 问 我最近在论坛上写了我的书 SQL Antipatterns.我给了他类似的答案:

This is very similar to a question a user asked me recently the forum for my book SQL Antipatterns. I gave him an answer similar to this:

$sql = "SELECT name, address, city FROM tableA JOIN tableB ON tableA.id = tableB.id";

$params = array();
$where = array();

if (isset($price) ) {
    $where[] = '(price = :price)';
    $params[':price'] = $price;
}
if (isset($sqft) ) {
    $where[] = '(sqft >= :sqft)';
    $params[':sqft'] = $sqft;
}
if (isset($bedrooms) ) {
    $where[] = '(bedrooms >= :bedrooms)';
    $params[':bedrooms'] = $bedrooms;
}

if ($where) {
  $sql .= ' WHERE ' . implode(' AND ', $where);
}

$stmt = $dbh->prepare($sql);

$stmt->execute($params);
$result_set = $stmt->fetchAll(PDO::FETCH_ASSOC);

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