如何从Prolog中的术语中获取原子变量列表 [英] How to get list of atom variables from a term in Prolog
本文介绍了如何从Prolog中的术语中获取原子变量列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何从术语中获取原子变量列表
例如-
Term = (h-5)* (h-5)+ (k- -2)* (k- -2)- (h-3)* (h-3)- (k-4)* (k-4)=0,get_variables(Term, Var_list).
对于上述术语,答案是Var_list = [h,k].
解决方案
以下代码在 SICStus Prolog 4.5.0 和 SWI-Prolog 8.0.0 上运行.
它基于 library(条款)
和 iwhen/2
:
:- use_module(library(terms)).atom_in(As, T) :-( \+ acyclic_term(T)->抛出(错误(类型错误(非循环项,T),_));iwhen(ground(T), setof(A, (sub_term(A,T),atom(A)), As))->真的;作为 = []).
使用 SWI-Prolog 8.0.0:
?- atom_in(Xs, (h-5)*(h-5)+(k- -2)*(k- -2)-(h-3)*(h-3)-(k-4)*(k-4)=0).Xs = [h, k].?- atom_in(Xs, f(g(a,b),h(c,d))).Xs = [a, b, c, d].?- atom_in(Xs, f(g(1,2),3)).Xs = [].?- atom_in(Xs, 1).Xs = [].
注意如何捕获和报告无效使用:
<预>?- atom_in(_, _).错误:参数未充分实例化?- atom_in(_, f(_)).错误:参数未充分实例化?- Term = f(a,Term), atom_in(_, Term).错误:类型错误:预期为acyclic_term",找到@(S_1,[S_1=f(a,S_1)])"(循环)How to get list of atom variables from a term
For example-
Term = (h-5)* (h-5)+ (k- -2)* (k- -2)- (h-3)* (h-3)- (k-4)* (k-4)=0,
get_variables(Term, Var_list).
For above term, the answer would be Var_list = [h,k].
解决方案
The following code runs with both SICStus Prolog 4.5.0 and SWI-Prolog 8.0.0.
It is based on library(terms)
and iwhen/2
:
:- use_module(library(terms)).
atoms_in(As, T) :-
( \+ acyclic_term(T)
-> throw(error(type_error(acyclic_term, T), _))
; iwhen(ground(T), setof(A, (sub_term(A,T),atom(A)), As))
-> true
; As = []
).
Using SWI-Prolog 8.0.0:
?- atoms_in(Xs, (h-5)*(h-5)+(k- -2)*(k- -2)-(h-3)*(h-3)-(k-4)*(k-4)=0).
Xs = [h, k].
?- atoms_in(Xs, f(g(a,b),h(c,d))).
Xs = [a, b, c, d].
?- atoms_in(Xs, f(g(1,2),3)).
Xs = [].
?- atoms_in(Xs, 1).
Xs = [].
Note how invalid uses are caught and reported:
?- atoms_in(_, _). ERROR: Arguments are not sufficiently instantiated ?- atoms_in(_, f(_)). ERROR: Arguments are not sufficiently instantiated ?- Term = f(a,Term), atoms_in(_, Term). ERROR: Type error: `acyclic_term' expected, found `@(S_1,[S_1=f(a,S_1)])' (a cyclic)
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