列表中的连续元素 [英] Consecutive elements in a list

问题描述

我阻止了 Prolog 中代码的谓词.我需要对这两个谓词进行编码:

I'm blocking on a predicate to code in Prolog. I need to code that two predicates:

如果我调用:u([a,b,c,d,e,f], X). 它将给出 X=[a,b], X=[b,c], X=[c,d] ...

If I call : u([a,b,c,d,e,f], X). it will give X=[a,b], X=[b,c], X=[c,d] ...

如果我调用:v([a,b,c,d,e,f], X). 它将给出 X=[a,b], X=[c,d], X=[e,f] ...

If I call : v([a,b,c,d,e,f], X). it will give X=[a,b], X=[c,d], X=[e,f] ...

非常感谢！

推荐答案

虽然 false 的回答更优雅，对于谓词 u/2，这里有一个更适合初学者的解决方案.

Although false's answer is more elegant, here is a solution more appropriate for beginners for your predicate u/2.

u([X,Y|_], [X,Y]).
u([_|Tail], XY):- u(Tail,XY).

第一条规则表示 [X,Y] 表示列表中的两个连续元素，如果它们是列表中的前两个元素.

The first rule says that [X,Y] represent two consecutive elements in a list if they are the first two elements in that list.

第二条规则规定，如果两个元素在列表尾部的某处连续，则它们在列表中是连续的.

The second rule states that two elements are consecutive in a list if they are consecutive somewhere in the tail of the list.

现在尝试为 v/2 找到类似的解决方案.

Now try to find a similar solution for v/2.

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