如何在两个 VM 之间使用 pyZMQ 发布/订阅 [英] How pub/sub with pyZMQ between two VMs

问题描述

我有两个 VM(VirtualBOx、Ubuntu 18.04 和 python-zmq)在同一台物理机 (Win10) 中运行.两台机器都配置为Bridge，可以ping通192.168.1.56-192.168.1.65.我遵循了本教程

解决方案

问:您是否尝试过这个，或者您知道可能是什么原因?"

是的，复制粘贴源代码(使用与您相同的 Scenario #2，有一个单独的 SUB ) 工作正常，而是使用下面修改后的代码模板.

---

A PUB-archetype Publisher :

使用 ZeroMQ v.2.11，py-2.7:

导入zmq随机导入导入系统导入时间上下文 = zmq.Context()尝试:socket = context.socket( zmq.PUB )socket.bind( "tcp://*:%s" % "5556" if len( sys.argv ) <2 else int( sys.argv[1] ) )socket.setsockopt( zmq.LINGER, 0 )为真:主题 = random.randrange( 9999, 10005 )messagedata = random.randrange(1, 215) - 80打印 "Topis = {0: >6d}: DATA = {1: >4d}".format( topic, messagedata )socket.send( "%d %d" % ( topic, messagedata ) )时间.sleep( 1 )除了:打印EXC'd here"最后:将优雅地关闭 Socket()-instance(s) 和 TERM Context()-instance(s)"socket.close()上下文.term()

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A SUB-原型监听器:

导入系统进口zmq上下文 = zmq.Context()尝试:socket = context.socket( zmq.SUB )打印将开始连接:用于进一步从天气服务器收集更新...";socket.connect( "tcp://localhost:%s" % "5556" if len( sys.argv ) <2 else int( sys.argv[1] ) )如果 len( sys.argv ) >2:socket.connect( "tcp://localhost:%s" % int( sys.argv[2] ) )socket.setsockopt( zmq.LINGER, 0 )# 订阅邮编，默认为NYC, 10001经过;topicfilter = "10001";socket.setsockopt( zmq.SUBSCRIBE, topicfilter )# 处理 5 个更新总价值 = 0对于范围 (5) 中的 update_nbr:字符串 = socket.recv()主题，消息数据 = string.split()total_value += int( messagedata )打印主题，消息数据打印更新:主题 '%s' 的平均 messagedata 值为 %dF";％(主题过滤器，total_value/update_nbr)除了:打印EXC'd here"最后:打印将优雅地关闭 Socket()-instance(s) 和 TERM Context()-instance(s)"；socket.close()上下文.term()

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您的分布式计算修改 SUB 端代码以定义无效的 TCP/IP 目标后，实验失败，其中代码由于显而易见的原因无法成功.connect().在此处阅读有关解决方案的信息.

I have two VMs (VirtualBOx, Ubuntu 18.04 and python-zmq) running within the same physical machine (Win10). Both machines are configured as Bridge and they can be ping successfully 192.168.1.56-192.168.1.65. I've followed this tutorial https://learning-0mq-with-pyzmq.readthedocs.io/en/latest/pyzmq/patterns/pubsub.html, however, it doesn't work. On one machine "server", the data is printed, however, at the subscriber "client", it doesn't receive anything.

Have you tried this or do you know which could be the cause?

解决方案

Q : "Have you tried this or do you know which could be the cause?"

Yes, a copy-paste source code ( used the same Scenario #2, as you did, having a solo SUB ) works fine, yet rather use the modified code template below.

---

A PUB-archetype Publisher :

Using ZeroMQ v.2.11, py-2.7:

import zmq
import random
import sys
import time

context = zmq.Context()
try:
    socket  = context.socket( zmq.PUB )
    socket.bind( "tcp://*:%s" % "5556" if len( sys.argv ) < 2 else int( sys.argv[1] ) )
    socket.setsockopt( zmq.LINGER, 0 )

    while True:
       topic       = random.randrange( 9999, 10005 )
       messagedata = random.randrange( 1, 215) - 80
       print "Topis = {0: >6d}: DATA = {1: >4d}".format( topic, messagedata )
       socket.send( "%d %d" % ( topic, messagedata ) )
       time.sleep( 1 )

except:
    print "EXC'd here"

finally:
    "WILL gracefully CLOSE Socket()-instance(s) and TERM Context()-instance(s)"
    socket.close()
    context.term()

---

A SUB-archetype Listener :

import sys
import zmq

context = zmq.Context()

try:
    socket = context.socket( zmq.SUB )
    
    print "WILL start connecting: for further collecting updates from weather server..."
    socket.connect( "tcp://localhost:%s" % "5556" if len( sys.argv ) < 2 else int( sys.argv[1] ) )

    if len( sys.argv ) > 2:
         socket.connect( "tcp://localhost:%s" % int( sys.argv[2] ) )

    socket.setsockopt( zmq.LINGER, 0 ) 

    # Subscribe to zipcode, default is NYC, 10001
    pass;                             topicfilter = "10001"
    socket.setsockopt( zmq.SUBSCRIBE, topicfilter )
    
    # Process 5 updates
    total_value = 0
    for update_nbr in range (5):
        string = socket.recv()
        topic, messagedata = string.split()
        total_value += int( messagedata )
        print topic, messagedata

    print "UPDATE: Average messagedata value for topic '%s' was %dF" % ( topicfilter, total_value / update_nbr )
      
except:
    print "EXC'd here"

finally:
    print "WILL gracefully CLOSE Socket()-instance(s) and TERM Context()-instance(s)"
    socket.close()
    context.term()

---

Your distributed-computing experiment fails after modifying the SUB-side code on defining an invalid TCP/IP-target where the code cannot, for obvious reasons, successfully .connect(). Go get a read about the solution here.

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