在 Puppet 中，如何访问已定义类型中的变量/属性? [英] In Puppet, how can I access a variable/attribute inside a defined type?

问题描述

我想在已定义类型的实例中引用变量.例如，我可以做什么来引用 b 中 foo a 的 $x 和 $y ?

I would like to reference variables inside instances of defined types. For example, what can I do to reference $x and $y of foo a in bar b?

 define foo($x, $y) {
  }

  define bar($foo) {
          notify { "${::$foo::x}": } # <- how to make this reference work?
  }

  foo { 'a':
          x => 'oh bar may you reference me',
          y => 'please'
  }

  bar { 'b':
          foo     => Foo['a'],
          require => Foo['a']
  }

我希望它起作用的原因是一个 foo 实例可能包含许多我不想重复给每个可能需要它们的资源的值.与其一遍又一遍地传递这些值，从而重复我自己，我宁愿传递对它们的容器的引用.

The reason why I would like this to work is that a foo instance may contain many values that I wouldn't like to repeat to each and every resource that might need them. Instead of passing those values again and again, thus repeating myself, I'd rather pass a reference to their container.

我一直在寻找并尝试了很多东西，但似乎无法在任何地方找到这个问题的答案.我知道可以修改属性、引用资源和读取类属性，但是否可以读取资源/定义类型的属性?如果不是，那么最好的解决方法是什么?

I've been looking all over and tried a bunch of things, but can't seem to find an answer to this question anywhere. I know it is possible to amend attributes, reference resources and read class attributes, but is it possible to read attributes of a resource/defined type? If it isn't what is then the best possible work around?

推荐答案

我实际上刚刚发现 Puppetlab 的 stdlib 模块 包含一个 getparam 函数 可以用来解决这个问题.

I've actually just found out that Puppetlab's stdlib module includes a getparam function that can be used to solve this problem.

所以这里终于解决了我自己的问题:

So here is finally the solution to my own question:

define foo($x, $y) {
}

define bar($foo) {
  notify { getparam(Foo[$foo], 'x'): }
  notify { getparam(Foo[$foo], 'y'): }
}

foo { 'a':
  x => 'oh bar may you reference me',
  y => 'please'
}

bar { 'b':
  foo  => 'a'
}

请注意 require =>Bar['b'] 定义中的 Foo['a'] 似乎不需要.

Please note that the require => Foo['a'] in the definition of Bar['b'] does not appear to be needed.

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